2017-07-01 156 views
0

我想写一个Python脚本来播放视频,但我得到这个权限错误:权限错误

Traceback (most recent call last): 
    File "alarm.py", line 17, in <module> 
    print play_video() 
    File "alarm.py", line 14, in play_video 
    p = subprocess.Popen([vlc_path, video]) 
    File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/subprocess.py", line 710, in __init__ 
    errread, errwrite) 
    File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/subprocess.py", line 1335, in _execute_child 
    raise child_exception 
OSError: [Errno 13] Permission denied 

我已经改变了权限,视频和两视频播放器为755(确认它们设置为-rwxrwxr-x),但除此之外,我无法想象要做什么。

alarm.py

import os 
import subprocess 


def play_video(): 
    video = "/path_to_video" 
    vlc_path = "/path_to_vlc" 
    p = subprocess.Popen([vlc_path, video]) 

if __name__ == '__main__': 
    print play_video() 
+0

他们的建议是只是为了确保权限级别是'-rwxrwxr-x',这是我做的第一件事。只需双重检查。 :( – thumbtackthief

+0

路径是完整的还是相对的?试图想想如果权限设置正确,可能导致这种情况的原因 – Parker

+0

@Parker Full。奇怪,对吧? – thumbtackthief

回答

0

不知道为什么我有我做无益的错误消息,但我有命令错误。它应该是:

p = subprocess.Popen(['open', '-a', vlc_path, video])