我在Python 2.7中使用tkinter
创建了一个Button
上的Button
以打开文件。它下面有一个Label
。我试图让它一旦打开文件,标签打印路径,“file1.name”或其他,在Label
,如果你打开一个新文件,它会改变Label
再次。python 2.7 Tk更改标签以从打开的文件中携带文件名
此外,我打赌有更好的方法来移动功能之间的数据比我在这里用global
,但这并不担心我现在。
我必须在功能之间移动打开的文件中的数据,以便我可以混合数据并保存到新文件中。该代码是:
from Tkinter import *
import Tkinter
import tkFileDialog
import tkMessageBox
root = Tkinter.Tk()
global rfile1
global rfile2
rfile1 = ""
rfile2 = ""
class Application(Frame):
def __init__(self, master = None):
Frame.__init__(self, master)
self.grid()
self.createWidgets1()
self.createLabels1()
self.createWidgets2()
self.createLabels2()
def createWidgets1(self):
self.oButton = Button(self, text = "open1", command = self.openfile1)
self.oButton.grid()
def createLabels1(self):
self.oLabel = Label(self, text = "whoops")
self.oLabel.grid()
def createWidgets2(self):
self.oButton = Button(self, text = "open2", command= self.openfile2)
self.oButton.grid()
def createLabels2(self):
self.oLabel2 = Label(self, text = "whoops2")
self.oLabel2.grid()
def openfile1(self):
file1 = tkFileDialog.askopenfile(title = "choose a file, *****", parent=root, mode = 'rb')
rfile1 = file1.read()
tkMessageBox.showinfo("oy", rfile1, parent=root)
def openfile2(self):
file2 = tkFileDialog.askopenfile(parent=root, mode='rb')
rfile2 = file2.read()
tkMessageBox.showinfo("hola", rfile2, parent=root)
app = Application()
app.master.title("whiggy whompus")
app.mainloop()
绝对起作用!非常感谢 : ) –