我收到错误“从字符串转换为uniqueidentifier时发生转换失败”,并且终于出现在我的绳索末端。我将问题缩小到尽可能小,同时保持错误的机智。如果要复制从这里首先安装CSV分流:在SQL Server中将字符串转换为uniqueidentifier错误时转换失败
http://www.sqlservercentral.com/articles/Tally+Table/72993/
这里的测试代码。我对SQL 2008 R2,但在数据库是SQL 2005兼容:
IF EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'[dbo].[ZZZTESTTABLE]') AND type in (N'U'))
DROP TABLE [dbo].[ZZZTESTTABLE]
GO
CREATE TABLE [dbo].[ZZZTESTTABLE](
[Col1] [uniqueidentifier] NOT NULL,
CONSTRAINT [PK_ZZZTESTTABLE] PRIMARY KEY CLUSTERED
(
[Col1] ASC
)WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]
) ON [PRIMARY]
-- Test table that I would like to check my values against
insert dbo.ZZZTESTTABLE(Col1) values('85B049B7-CDD0-4995-B582-5A74523039C0')
-- Test string that will be split into table in the DelimitedSplit8k function
declare @temp varchar(max) = '918E809E-EA7A-44B5-B230-776C42594D91,6F8DBB54-5159-4C22-9B0A-7842464360A5'
-- I'm trying to delete all data in the ZZZTESTTABLE that is not in my string but I get the error
delete dbo.ZZZTESTTABLE
where Col1 not in
(
-- ERROR OCCURS HERE
select cast(Item as uniqueidentifier) from dbo.DelimitedSplit8K(@temp, ',')
)
这里的DelimitedSplit8K函数的源,所以你不必去寻找它:
CREATE FUNCTION dbo.DelimitedSplit8K
--===== Define I/O parameters
(@pString VARCHAR(8000), @pDelimiter CHAR(1))
RETURNS TABLE WITH SCHEMABINDING AS
RETURN
--===== "Inline" CTE Driven "Tally Table" produces values from 0 up to 10,000...
-- enough to cover VARCHAR(8000)
WITH E1(N) AS (
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1
), --10E+1 or 10 rows
E2(N) AS (SELECT 1 FROM E1 a, E1 b), --10E+2 or 100 rows
E4(N) AS (SELECT 1 FROM E2 a, E2 b), --10E+4 or 10,000 rows max
cteTally(N) AS (--==== This provides the "zero base" and limits the number of rows right up front
-- for both a performance gain and prevention of accidental "overruns"
SELECT 0 UNION ALL
SELECT TOP (DATALENGTH(ISNULL(@pString,1))) ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) FROM E4
),
cteStart(N1) AS (--==== This returns N+1 (starting position of each "element" just once for each delimiter)
SELECT t.N+1
FROM cteTally t
WHERE (SUBSTRING(@pString,t.N,1) = @pDelimiter OR t.N = 0)
)
--===== Do the actual split. The ISNULL/NULLIF combo handles the length for the final element when no delimiter is found.
SELECT ItemNumber = ROW_NUMBER() OVER(ORDER BY s.N1),
Item = SUBSTRING(@pString,s.N1,ISNULL(NULLIF(CHARINDEX(@pDelimiter,@pString,s.N1),0)-s.N1,8000))
FROM cteStart s
;
我会怀疑分裂功能,因为那是复杂性。如果您添加一个WHERE项目不是空和LEN(Item)> 1到分割选择,它是否仍然会给出错误? – hatchet
“我刚在网上找到一些随机脚本,我不明白它是如何工作的,但我打算使用,有人可以为我调试吗?” –
分割功能似乎没问题。我也想知道为什么你的删除不能像写入那样工作。如果改写为EXISTS,它将以相同的方式失败。 – hatchet