在Python中迭代和打印JSON对象

我有一个Google Spreadsheet，我想用Python获取，然后通过JSON处理它。这是中途工作，并通过Stackoverflow几个小时后，我认为是时候提出一个问题。在Python中迭代和打印JSON对象

例如，JSON文件的格式如下所示（来自https://developers.google.com/gdata/docs/json）。

{ 
    "version": "1.0", 
    "encoding": "UTF-8", 
    "feed": { 
    "xmlns": "http://www.w3.org/2005/Atom", 
    "xmlns$openSearch": "http://a9.com/-/spec/opensearchrss/1.0/", 
    "xmlns$gd": "http://schemas.google.com/g/2005", 
    "xmlns$gCal": "http://schemas.google.com/gCal/2005", 
    "id": {"$t": "..."}, 
    "updated": {"$t": "2006-11-12T21:25:30.000Z"}, 
    "title": { 
     "type": "text", 
     "$t": "Google Developer Events" 
    }, 
    "subtitle": { 
     "type": "text", 
     "$t": "The calendar contains information about upcoming developer 
     conferences at which Google will be speaking, along with other 
     developer-related events." 
    }, 
    "link": [{ 
     "rel": "...", 
     "type": "application/atom+xml", 
     "href": "..." 
     },{ 
     "rel": "self", 
     "type": "application/atom+xml", 
     "href": "..." 
    }], 
    "author": [{ 
     "name": {"$t": "Google Developer Calendar"}, 
     "email": {"$t": "[email protected]"} 
    }], 
    "generator":{ 
     "version": "1.0", 
     "uri": "http://www.google.com/calendar", 
     "$t": "Google Calendar" 
    }, 
    "openSearch$startIndex": {"$t": "1"}, 
    "openSearch$itemsPerPage": {"$t": "25"}, 
    "gCal$timezone": {"value": "America/Los_Angeles"}, 

    "entry": [{ 
     "id": {"$t": "..."}, 
     "published": {"$t": "2006-11-12T21:25:30.000Z"}, 
     "updated": {"$t": "2006-11-12T21:25:30.000Z"}, 
     "category": [{ 
     "scheme": "...", 
     "term": "..." 
     }], 
     "title":{ 
     "type": "text", 
     "$t": "WebmasterWorld PubCon 2006: Google Developer Tools in General" 
     }, 
     "content": { 
     "type": "text", 
     "$t": "Google is sponsoring at 
      <a href=\"http://www.pubcon.com/\">WebmasterWorld PubCon 2006</a>. 
      \n Come and visit us at the booth or join us for an evening demo 
      reception where we will be talking \"5 ways to enhance your website 
      with Google Code\". \n After all, \n it is Vegas, baby! See you soon." 
     }, 
     "link": [{ 
     "rel": "alternate", 
     "type": "text/html", 
     "href": "...", 
     "title": "alternate" 
     },{ 
     "rel": "self", 
     "type": "application/atom+xml", 
     "href": "..." 
     }], 
     "author": [{ 
     "name": {"$t": "Google Developer Calendar"}, 
     "email": {"$t": "[email protected]"} 
     }], 
     "gd$transparency": {"value": "http://schemas.google.com/g/2005#event.opaque"}, 
     "gd$eventStatus": {"value": "http://schemas.google.com/g/2005#event.confirmed"}, 
     "gd$comments": {"gd$feedLink": {"href": "..."}}, 
     "gCal$sendEventNotifications": {"value": "true"}, 
     "gd$when": [{ 
     "startTime": "2006-11-15", 
     "endTime": "2006-11-17", 
     "gd$reminder": [{"minutes": "10"}] 
     }], 
     "gd$where": [{"valueString": "3150 Paradise Road,Las Vegas,NV 89109"}]}, 
    }] 
    } 
}

我的Python代码如下：

import requests, json 
r = requests.get('link-to-google-spreadsheet-json') 
j = r.json()

测试JSON文件输出的顶级层次结构如下：

>>> print j["version"] 
1.0

但遍历的对象，像这样：

for feed in j["feed"]: 
    for entry in feed["entry"]: 
     for title in entry["title"]: 
      print title["$t"] 
     print 
    print

给我以下错误：

Traceback (most recent call last): 
File "<console>", line 2, in <module> 
TypeError: string indices must be integers.

它听起来像是要从字符串打印单个字母，只要我给索引号。那么如何解析JSON，以便正确输出我想要的内容（例如feed - > entry - > title - > $ t）？

来源

2012-12-30 AAA

我已经使用Google的示例发布了JSON文件的格式，因此您可以在feed - > entry - > title - > $ t中看到我正在尝试获取$ t的值。 – AAA

我完全忽略了> _>我删除了我以前的评论。 – Natan

j ['feed']是一本字典。你的代码应该是这样的：

for entry in j['feed']['entry']: 
    print entry['title']['$t']

来源

2012-12-30 08:31:12 sneawo

谢谢。你能介绍一下我如何访问字典，而不是你生成的代码吗？ – AAA

当你迭代j ['feed']时，你遍历它的关键字：category，updated，... – sneawo

feed和title的字典没有列出，所以你不应该有环路他们。您只需要一个for-loop用于入口列表。

来源

2012-12-30 10:52:19 Lycha

在Python中迭代和打印JSON对象

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