处理按钮和EditText发送短信

Question

我想处理EditText和我的listView中的按钮发送短信。 到目前为止，电话号码是由用户输入的。所以，我做了一个适配器，如下：

public class ListViewStudentWithDateAdapter extends ArrayAdapter<ListViewStudentWithDate> { 
private Context mContext; 
private ArrayList<ListViewStudentWithDate> mData; 
private EditText Parent_Number ; 

public ListViewStudentWithDateAdapter (Context mContext, ArrayList<ListViewStudentWithDate> mData) 
{ 
    super(mContext, R.layout.student_list_with_date_shape, mData); 
    this.mContext = mContext; 
    this.mData = mData; 
} 
public int getCount() { 
    return mData.size(); 
} 

@Override 
public long getItemId(int position) { 
    return position; 
} 

@Override 
public View getView(final int position, View convertView, ViewGroup parent) 
{ 
    if (convertView == null) { 
     LayoutInflater mInflater = (LayoutInflater) 
       mContext.getSystemService(Activity.LAYOUT_INFLATER_SERVICE); 
     convertView = mInflater.inflate(R.layout.student_list_with_date_shape, null); 
    } 
    TextView Name = (TextView) convertView.findViewById(R.id.Name); 
    Name.setText(mData.get(position).getStudent_name()); 

    TextView GRADE = (TextView) convertView.findViewById(R.id.GRADE_ID); 
    GRADE.setText(mData.get(position).getGrade_id()); 

    TextView CLASS = (TextView) convertView.findViewById(R.id.CLASS_ID); 
    CLASS.setText(mData.get(position).getCLass_id()); 

    Parent_Number = (EditText) convertView.findViewById(R.id.Father_number); 

    Button Send_Father = (Button) convertView.findViewById(R.id.Send_Father); 
    Send_Father.setOnClickListener(new View.OnClickListener() { 
     @Override 
     public void onClick(View view) { 
      Log.i("Send SMS", ""); 
      String phoneNo = Parent_Number.getText().toString(); 
      String sms = "HELLO World" ; 
      try { 
       // Get the default instance of the SmsManager 
       SmsManager smsManager = SmsManager.getDefault(); 
       smsManager.sendTextMessage(phoneNo, 
         null, 
         sms, 
         null, 
         null); 
       Toast.makeText(getContext(), "Your sms has successfully sent!", 
         Toast.LENGTH_LONG).show(); 
      } catch (Exception ex) { 
       Toast.makeText(getContext(),"Your sms has failed...", 
         Toast.LENGTH_LONG).show(); 
       ex.printStackTrace(); 
      } 
     } 
    }); 
    return convertView; 
} 

} 

它似乎并不奏效，因为它总是给我的失败消息。任何想法 ？？

Answer 1

你最有可能得到一个IllegalArgumentException因为你传递给sendTextMessage()数为空。 Parent_Number是一个类成员，它将保留对由getView()调用创建的最后一个实例的引用，该实例不一定是您当前正在编辑的那个实例。

你需要缓存Parent_NumberEditText在Send_FatherButton的标签，并检索它和它在onClick()方法文本：

public View getView(final int position, View convertView, ViewGroup parent) 
{ 
    ... 
    Parent_Number = (EditText) convertView.findViewById(R.id.Father_number); 
    Button Send_Father = (Button) convertView.findViewById(R.id.Send_Father); 

    Send_Father.setTag(Parent_Number); 
    Send_Father.setOnClickListener(new View.OnClickListener() { 
      @Override 
      public void onClick(View view) { 
       Log.i("Send SMS", ""); 
       EditText parent = (EditText) view.getTag(); 
       String phoneNo = parent.getText().toString(); 
       String sms = "HELLO World" ; 
       try { 
        // Get the default instance of the SmsManager 
        SmsManager smsManager = SmsManager.getDefault(); 
        smsManager.sendTextMessage(phoneNo, 
               null, 
               sms, 
               null, 
               null); 
        Toast.makeText(getContext(), "Your sms has successfully sent!", 
            Toast.LENGTH_LONG).show(); 
       } catch (Exception ex) { 
        Toast.makeText(getContext(),"Your sms has failed...", 
            Toast.LENGTH_LONG).show(); 
        ex.printStackTrace(); 
       } 
      } 
     }); 
    return convertView; 
} 

Answer 2

检查清单为persmission：

<uses-permission android:name="android.permission.SEND_SMS" /> 

我觉得你的电话号码是空在那里，调试它