对于文本bozo__foo!!bar.baz
,如何将包含这个的NSString拆分为(bozo, foo, bar, baz)
?拆分NSString与多个分隔符?
也就是说,将其与具有字符串(分隔符)__
,!!
和.
的组件分开。
对于文本bozo__foo!!bar.baz
,如何将包含这个的NSString拆分为(bozo, foo, bar, baz)
?拆分NSString与多个分隔符?
也就是说,将其与具有字符串(分隔符)__
,!!
和.
的组件分开。
您可以使用NSCharacterSet分割字符串。试试这个
NSString *[email protected]"bozo__foo!!bar.baz";
NSString *sep = @"_!.";
NSCharacterSet *set = [NSCharacterSet characterSetWithCharactersInString:sep];
NSArray *temp=[test componentsSeparatedByCharactersInSet:set];
NSLog(@"temp=%@",temp);
NSString *text = @"bozo__foo!!bar.baz";
NSArray *split1 = [text componentsSeparatedByString:@"__"];
NSArray *split2 = [[split1 lastObject] componentsSeparatedByString:@"!!"];
NSArray *split3 = [[split2 lastObject] componentsSeparatedByString:@"."];
NSLog(@"%@, %@, %@, %@", split1[0], split2[0], split3[0], split3[1]);
作为回答,如果这些分裂没有下令将无法正常工作,但因为在我的情况是这样,那么我将其标记。 – Matoe
我知道这个问题已经被回答了,但这是一种使用多个字符串分隔字符串的方法。这是一个类别到NSString。
- (NSArray<NSString *> *)componentsSeparatedByStrings:(NSArray<NSString *> *)separators
{
NSMutableArray<NSString *> *components = [[NSMutableArray alloc] init];
unichar buffer[self.length + 1];
NSInteger currentOrigin = 0;
NSInteger currentLength = 0;
[self getCharacters:buffer];
for(NSInteger i = 0; i < self.length; i++)
{
unichar currentChar = buffer[i];
currentLength++;
for(NSInteger n = 0; n < separators.count; n++)
{
NSString *currentDivider = [separators objectAtIndex:n];
if(currentDivider.length == 0)
{
return @[self];
}
else if(currentDivider.length > 1)
{
BOOL goodMatch = NO;
for(NSInteger x = 0; x < currentDivider.length; x++)
{
unichar charInDivider = [currentDivider characterAtIndex:x];
if(charInDivider == currentChar)
{
goodMatch = YES;
}
else
{
goodMatch = NO;
break;
}
if(goodMatch == YES && ((x + 1) != currentDivider.length))
{
i++;
currentLength++;
currentChar = buffer[i];
}
}
if(goodMatch == YES)
{
NSRange newComponentRange = NSMakeRange(currentOrigin, (currentLength - currentDivider.length));
NSString *newComponent = [self substringWithRange:newComponentRange];
currentOrigin = (i + 1);
currentLength = 0;
[components addObject:newComponent];
NSLog(@"%@", components);
}
}
else // If current divider is only one character long.
{
if([currentDivider characterAtIndex:0] == currentChar)
{
NSRange newComponentRange = NSMakeRange(currentOrigin, (currentLength - 1));
NSString *newComponent = [self substringWithRange:newComponentRange];
currentOrigin = (i + 1);
currentLength = 0;
[components addObject:newComponent];
break;
}
}
}
// Handle the end of the string.
if((i + 1) == self.length)
{
NSRange newComponentRange = NSMakeRange(currentOrigin, currentLength);
NSString *newComponent = [self substringWithRange:newComponentRange];
currentOrigin = 0;
currentLength = 0;
[components addObject:newComponent];
}
}
return components;
}
示例: “ABCD__EFGHI__JKLMNOP-QRST.UV_WXYZ”
NSLog(@"%@", [test componentsSeparatedByStrings:@[@"__", @"-", @"."]]);
登录结果: “(ABCD, EFGHI, JKLMNOP, QRST, "UV_WXYZ")
”
更多官能解决方案是应用-componentsSeparatedByString:
递归,对于每个部件,这是在以前的分离器应用中得到的:
的NSString类别
- (NSMutableArray<NSString *> *)gvr_componentsSeparatedByStrings:(NSArray<NSString *> *)separators {
if (separators.count == 0) {
return [NSMutableArray arrayWithObject:self];
}
NSString *separator = [separators firstObject];
NSArray *reducedSeparators = [separators gvr_arrayByRemovingFirstObject];
NSArray *components = [self componentsSeparatedByString:separator];
NSMutableArray *result = [NSMutableArray new];
for (NSString *component in components) {
NSMutableArray *subResult = [component gvr_componentsSeparatedByStrings:reducedSeparators];
[result addObjectsFromArray:subResult];
}
return result;
}
NSArray的范畴
- (NSArray *)gvr_arrayByRemovingFirstObject {
NSMutableArray *result = [NSMutableArray new];
for (NSInteger i = 1; i < self.count; i++) {
[result addObject:self[i]];
}
return [result copy];
}
如果'sep'不是一个字符,就可以工作。例如如果我想用'!!'而不是'!'来分割 – Arefly