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我有一个要求是我必须编写一个高性能的文件搜索程序，该程序应该列出与从最顶层文件夹开始提供的名称模式相匹配的所有文件和文件夹，以及在子文件夹中递归搜索。文件搜索高性能程序
程序可以是命令行主类具有以下输入
的顶层文件夹以启动搜索。示例是C：\ MyFolders 要搜索的项目的类型。文件或文件夹或两者 搜索模式的Java正则表达式（java.util.regex中）被接受为paatern
例如MFILE .tx？会发现应用程序必须返回的UMFile123.txt和AIIMFile.txs' 超时（以秒为单位）。否则必须以“无法完成操作”消息返回。
我想出了anoter做法是..
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.List;
import com.sapient.test.fileSearch.FileSearch;
public class FilesearchMain {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
int flag=0;
System.out.println("Type Item to Search ");
System.out.println("1 File");
System.out.println("2 Folder ");
System.out.println("3 Both");
System.out.println("0 Exit");
try{
BufferedReader readType = new BufferedReader(new InputStreamReader(System.in));
String searchType =readType.readLine();;
System.out.println("Enter name of file to search ::");
BufferedReader readName = new BufferedReader(new InputStreamReader(System.in));
String fileName=readName.readLine();
if(searchType==null && fileName==null){
throw new Exception("Error Occured::Provide both the input Parameters");
}
validateInputs(searchType,fileName);
FileSearch fileSearch = new FileSearch(searchType,fileName);
List resultList=fileSearch.findFiles();
System.out.println(resultList);
}catch(IOException io){
System.out.println("Error Occured:: Check the input Parameters and try again");
}catch(Exception e){
System.out.println(e.getMessage());
}
}
private static void validateInputs(String searchType, String fileName)
throws Exception{
if(!(searchType.equals("1") || searchType.equals("2") || searchType.equals("3"))){
throw new Exception("Error:: Item to search can be only 1 or 2 or 3");
}
if(searchType.equals("") || fileName.equals("")){
System.out.println("Error Occured:: Check the input Parameters and try again");
}
}
}
其他文件...
public class FileSearch {
private String searchType;
private String fileName;
public FileSearch(){
}
public FileSearch(String sType,String fName){
this.searchType=sType;
this.fileName=fName;
}
public String getSearchType() {
return searchType;
}
public void setSearchType(String searchType) {
this.searchType = searchType;
}
public String getFileName() {
return fileName;
}
public void setFileName(String fileName) {
this.fileName = fileName;
}
public List findFiles(){
File file = new File("C:\\MyFolders");
return searchInDirectory(file);
}
//Assuming that files to search should contain the typed name by the user
//
private List searchInDirectory(File dirName){
List<String> filesList = new ArrayList<String>();
if(dirName.isDirectory()){
File [] listFiles = dirName.listFiles();
for(File searchedFile : listFiles){
if(searchedFile.isFile() && searchedFile.getName().toUpperCase().contains(getFileName().toUpperCase())&&
(getSearchType().equals("1") || getSearchType().equals("3"))){
filesList.add(searchedFile.getName());
}else if(searchedFile.isDirectory() && searchedFile.getName().toUpperCase().contains(getFileName().toUpperCase())
&& (getSearchType().equals("2") || getSearchType().equals("3"))){
filesList.add(searchedFile.getName());
searchInDirectory(searchedFile);
}else{
searchInDirectory(searchedFile);
}
}
}
return filesList;
}
}
Please advise is this approach is correct as per design..!
有没有你为什么选择不使用'File.listFiles（的FileFilter）'任何理由？ – MadProgrammer 2012-08-06 05:42:21
@MadProgrammer你能否请更正我错了更新后的帖子..！ – user1577449 2012-08-06 05:46:43
@ user1577449：他正确地建议你应该对内置函数进行基准测试，看看它是否足够好，然后再重新创建它。以下是一个示例：http://docs.oracle.com/javase/tutorial/essential/io/find.html。或者这个：http：//www.exampledepot.com/egs/java.io/GetFiles.html – paulsm4 2012-08-06 05:47:38