我左边的连接错误？

Question

今天我在想咖啡不够强壮。我需要查询表fb-celebotd以获得与fb-celebotd.celebdate相匹配的照片。大部分其他需要的信息都依赖于照片表。

以下是给我一个MySQL错误：

Select photos.*,photographer.name, events.eventname, events.eventhome, subevents.subeventname, photodir.photodir, fb-celebotd.celebdate, fb-celebotd.trivia 
     from photos 
LEFT JOIN fb-celebotd ON (photos.photoid = fb-celebotd.photoid) 
LEFT JOIN photodir ON (photos.photodirid = photodir.photodirid) 
LEFT JOIN photographer ON (photos.photographerid = photographer.photographerid) 
LEFT JOIN events ON (photos.eventid = events.eventid) 
LEFT JOIN subevents ON (photos.subeventid = subevents.subeventid) 
WHERE fb-celebotd.celebdate=1277092800 

这是可行的在一个查询或我必须首先查询FB-celebotd为PHOTOID和琐事，然后查询基础上，PHOTOID其他表？

谢谢。

Answer 1

应该fb-celebotd（带短划线）是fb_celebotd（带下划线）？如果表名有短划线，则必须引用表名："fb-celebotd"。否则，短划线被视为一个负号，并尝试从fb中减去celebotd（都是未知的）。

Answer 2

如果你真的有一个名为FB-celebotd表，那么你需要使用它在查询中每次引用表名：我知道我的咖啡是弱

Select photos.*,photographer.name, events.eventname, events.eventhome, subevents.subeventname, photodir.photodir, `fb-celebotd`.celebdate, `fb-celebotd`.trivia 
     from photos 
LEFT JOIN `fb-celebotd` ON (photos.photoid = `fb-celebotd`.photoid) 
LEFT JOIN photodir ON (photos.photodirid = photodir.photodirid) 
LEFT JOIN photographer ON (photos.photographerid = photographer.photographerid) 
LEFT JOIN events ON (photos.eventid = events.eventid) 
LEFT JOIN subevents ON (photos.subeventid = subevents.subeventid) 
WHERE `fb-celebotd`.celebdate=1277092800