2016-01-06 30 views
1

试图创建与jsonresult和ajax级联dropdownmenu,但我不明白为什么我得到500内部服务器错误。500内部服务器错误JsonResult mvc asp.net

[HttpGet] 
    public JsonResult GetModels(string brandID="") 
    { 
     List<Model> models = new List<Model>(); 
     int ID = 0; 
     if (int.TryParse(brandID, out ID)) 
     { 
      using (CarsEntities1 dc = new CarsEntities1()) 
      { 
     models = dc.Models.Where(a => a.Brand_ID == ID).OrderBy(a =>a.Model_name).ToList(); 
      } 
     } 
     if (Request.IsAjaxRequest()) 
     { 

      return new JsonResult 
      { 
       Data = models, 
       JsonRequestBehavior = JsonRequestBehavior.AllowGet 
      }; 
     } 
     else 
     { 
      return new JsonResult 
      { 
       Data = "Not valid request", 
       JsonRequestBehavior = JsonRequestBehavior.AllowGet 
      }; 
     } 
    } 

我使用的方法来传递项目的列表为DropDownMenu和下面的代码试图输出列表:

$(document).ready(function() { 
     //if (typeof ($) == 'function') alert('jQuery is loaded.'); 
     $("#brand_Brand_ID").change(function() { 
      // this will call when Brand Dropdown select change 
      var brandID = parseInt($("#brand_Brand_ID").val()); 
      if (!isNaN(brandID)) { 
       var ddModel = $("#Model_ID"); 
       ddModel.empty(); // this line is for clear all items from Model dropdown 
       ddModel.append($("<option></option").val("").html("Select model")); 
       // Here I will call Controller Action via Jquery to load Model for selected Brand 
       $.ajax({ 
        url: "@Url.Action("GetModels","ModelSpec")", 
        type: "GET", 
        data: { brandID: brandID }, 
        dataType: "json", 
        success: function (data) { 
         if (data != null && data.success) { 
          $.each(data, function (i, val) { 
           ddModel.append(
             $("<option></option>").val(val.Model_ID).html(val.Model_name) 
            ); 
          }); 
         } 
        }, 
        error: function() { 
         alert("Fail"); 

        } 
       }); 
      } 
     }); 
    }); 

我得到的是上面下面的方法出现错误以下: GET http://localhost:2508/ModelSpec/GetModels?brandID=2 500内部服务器错误的jquery-1.7.1.js(线8102)

此外,我注意到穿过GetModels方法世界上没有数据时犯规发生错误。有时我得到: GET/ModelSpec/GetModels?brandID = 5 401未授权

只要GetModels返回任何错误发生,否则不会。

The ObjectContext instance has been disposed and can no longer be used for operations that require a connection

堆栈跟踪: http://pastebin.com/3aXg7YiM

+2

您能否粘贴错误描述?它将在错误回调中提供,甚至可以使用开发人员工具。 – gustavodidomenico

+0

另外,您可以在操作中放置断点以查看其失败的位置 –

+0

您可以用'int brandID'在方法声明中替换'string brandID =“”'。然后你可以删除这个控件:'int.TryParse(brandID,out ID)'。也许它会解决问题,但可能不会。你可以试试吗? – erikscandola

回答

1

你需要移动使用块内的return语句 返回语句执行

public JsonResult GetModels(int brandID) 
{ 
    List<Model> models = new List<Model>(); 

    using (CarsEntities1 dc = new CarsEntities1()) 
    { 
     models = dc.Models.Where(a => a.Brand_ID == brandID).OrderBy(a =>a.Model_name); 
     if (Request.IsAjaxRequest()) 
     { 
      return new JsonResult 
      { 
       Data = models.ToList(), 
       JsonRequestBehavior = JsonRequestBehavior.AllowGet 
      }; 
     } 
    } 

    return new JsonResult 
    { 
     Data = "Not valid request", 
     JsonRequestBehavior = JsonRequestBehavior.AllowGet 
    };  
} 
+0

试过但没有改变。 –

0

json的返回类型之前,数据库上下文设置必须是原始的,所以我改变了相应的代码(交换List to String []和OrderBy来选择:

public JsonResult GetModels(int brandID) 
{ 
String[] models; 

using (CarsEntities1 dc = new CarsEntities1()) 
{ 
    models = dc.Models.Where(a => a.Brand_ID == brandID).Select(a=> a.Model_name).toArray(); 
    if (Request.IsAjaxRequest()) 
    { 
     return new JsonResult 
     { 
      Data = models, 
      JsonRequestBehavior = JsonRequestBehavior.AllowGet 
     }; 
    } 
} 

return new JsonResult 
{ 
    Data = "Not valid request", 
    JsonRequestBehavior = JsonRequestBehavior.AllowGet 
};  
}