0
let animal["legs"] = currentAnimal.legCount
let animal["canFly"] = currentAnimal.canFly
let animal["chicken"] = currentAnimal.isSoonToBeNugget
let anim....
其中之一是nil
。我的这些约10想每个值打印到控制台,而不必去分配变量并打印
print(animal["legs"])
print(animal["canFly"])
print(animal["chicken"])
print(anim....)
什么是最简洁的方式来做到这一点?