sql中跳过包含字符串

Question

您好我需要跳过可能包含文本

示例行的行：我有表OUTSTANDING和我的领域如下。

INVOICENO 
AB1  
111 
ZX3 

我需要跳过行包含AB1和ZX3，并选择包含111

行我曾尝试此查询

"SELECT * FROM [INT]..OUTSTANDING WHERE INVOICENO NOT LIKE '%[a-z,-]%'"; 

Answer 1

尝试：

"SELECT * FROM [INT]..OUTSTANDING WHERE NOT INVOICENO LIKE '%[0-9]%'"; 

或

...where INVOICENO not like '%[a-z]%' 

除非需要更高级的正则表达式....
源：http://www.sqllion.com/2010/12/pattern-matching-regex-in-t-sql/

Answer 2

WHERE ISNUMERIC(INVOICENO) = 1 

http://technet.microsoft.com/en-us/library/ms186272.aspx

Answer 3

Select * 
FROM [INT]..OUTSTANDING 
WHERE IsNumeric(INVOICENO) = 1 
And INVOICENO Is Not NULL 

Answer 4

尝试以下mothods：

方法1：

SELECT * 
FROM [INT]..OUTSTANDING 
WHERE InvoiceNo IS NOT NULL 
    AND ISNUMERIC(InvoiceNo)=1 

Mehod 2：

SELECT * 
FROM [INT]..OUTSTANDING 
WHERE InvoiceNo IS NOT NULL 
    AND INVOICENO NOT LIKE '%[^0-9]%'