火力地堡用户registeration

Question

我在Android应用的开发相当新，我试图让从那里用户可以注册到数据库中的活动，这是代码

public class RegisterActivity extends AppCompatActivity { 

    TextInputLayout mEmail, mPassword; 
    Button mRegisterButton; 
    FirebaseAuth mAuth; 
    Button loginAccountButton; 
    ProgressDialog progressDialogue; 

    @Override 
    protected void onCreate(Bundle savedInstanceState) { 
     super.onCreate(savedInstanceState); 
     setContentView(R.layout.activity_register); 

     mPassword = (TextInputLayout) findViewById(R.id.password); 
     mEmail = (TextInputLayout) findViewById(R.id.email); 
     loginAccountButton = (Button) findViewById(R.id.loginalready); 
     mRegisterButton = (Button) findViewById(R.id.registerButton); 
     progressDialogue = new ProgressDialog(RegisterActivity.this); 

     mAuth = FirebaseAuth.getInstance(); 

     loginAccountButton.setOnClickListener(new View.OnClickListener() { 
      @Override 
      public void onClick(View v) { 
       startActivity(new Intent(RegisterActivity.this,login.class)); 
      } 
     }); 

     mRegisterButton.setOnClickListener(new View.OnClickListener() { 
      @Override 
      public void onClick(View v) { 
       registeruser(); 
      } 

      private void registeruser() { 
       String email = mEmail.getEditText().getText().toString().trim(); 
       String password = mPassword.getEditText().getText().toString().trim(); 
       progressDialogue.setMessage("Please wait"); 
       progressDialogue.show(); 
       mAuth.createUserWithEmailAndPassword(email,password) 
         .addOnCompleteListener(new OnCompleteListener<AuthResult>() { 
          @Override 
          public void onComplete(@NonNull Task<AuthResult> task) { 
           if(task.isSuccessful()){ 
            progressDialogue.dismiss(); 
            Toast.makeText(RegisterActivity.this,"You're now registered",Toast.LENGTH_LONG).show(); 
            startActivity(new Intent(RegisterActivity.this,MainActivity.class)); 
            finish(); 
           } 
           else{ 
            Toast.makeText(RegisterActivity.this,"Something went horribly wrong",Toast.LENGTH_LONG).show(); 
           } 
          } 
         }); 

      } 
     }); 



}} 

所有的类都正确导入和似乎是没有办法解决它，代码是工作了几个小时前，但现在它只是不会让步每次我试图和运行它给我的代码吐司出事了可怕的错误

this is the activity_register.xml 

<android.support.design.widget.TextInputLayout 
    android:layout_width="368dp" 
    android:layout_height="wrap_content" 
    android:id="@+id/email" 
    android:layout_marginRight="8dp" 
    app:layout_constraintRight_toRightOf="parent" 
    android:layout_marginLeft="8dp" 
    app:layout_constraintLeft_toLeftOf="parent" 
    tools:layout_editor_absoluteY="8dp"> 

    <EditText 
     android:layout_width="match_parent" 
     android:layout_height="wrap_content" 
     android:hint="EMAIL" /> 
</android.support.design.widget.TextInputLayout> 

<android.support.design.widget.TextInputLayout 
    android:layout_width="368dp" 
    android:layout_height="wrap_content" 
    android:layout_marginTop="8dp" 
    app:layout_constraintTop_toBottomOf="@+id/email" 
    android:id="@+id/password" 
    android:layout_marginLeft="8dp" 
    app:layout_constraintLeft_toLeftOf="parent" 
    android:layout_marginRight="8dp" 
    app:layout_constraintRight_toRightOf="parent"> 

    <EditText 
     android:layout_width="match_parent" 
     android:layout_height="wrap_content" 
     android:hint="PASSWORD" /> 
</android.support.design.widget.TextInputLayout> 

<Button 
    android:id="@+id/registerButton" 
    android:layout_width="wrap_content" 
    android:layout_height="wrap_content" 
    android:layout_marginTop="25dp" 
    android:text="REGISTER" 
    app:layout_constraintTop_toBottomOf="@+id/password" 
    tools:layout_editor_absoluteX="280dp" /> 

<Button 
    android:id="@+id/loginalready" 
    android:layout_width="wrap_content" 
    android:layout_height="wrap_content" 
    android:layout_marginBottom="0dp" 
    android:layout_marginLeft="8dp" 
    android:layout_marginRight="8dp" 
    android:text="login" 
    android:textSize="14sp" 
    app:layout_constraintBottom_toBottomOf="parent" 
    app:layout_constraintLeft_toLeftOf="parent" 
    app:layout_constraintRight_toRightOf="parent" 
    tools:text="login?" 
    android:layout_marginTop="8dp" 
    app:layout_constraintTop_toBottomOf="@+id/password" 
    app:layout_constraintVertical_bias="0.051" /> 

Answer 1

给android:id=""你EditText，而不是TextInputLayout如下

<android.support.design.widget.TextInputLayout 
    android:layout_width="368dp" 
    android:layout_height="wrap_content" 
    android:layout_marginTop="8dp" 
    app:layout_constraintTop_toBottomOf="@+id/displayName" 
    android:layout_marginRight="8dp" 
    app:layout_constraintRight_toRightOf="parent" 
    android:layout_marginLeft="8dp" 
    app:layout_constraintLeft_toLeftOf="parent"> 

    <EditText 
     android:layout_width="match_parent" 
     android:layout_height="wrap_content" 
     android:id="@+id/email" 
     android:hint="EMAIL" /> 
</android.support.design.widget.TextInputLayout> 

<android.support.design.widget.TextInputLayout 
    android:layout_width="368dp" 
    android:layout_height="wrap_content" 
    android:layout_marginTop="8dp" 
    app:layout_constraintTop_toBottomOf="@+id/email" 
    android:layout_marginLeft="8dp" 
    app:layout_constraintLeft_toLeftOf="parent" 
    android:layout_marginRight="8dp" 
    app:layout_constraintRight_toRightOf="parent"> 

    <EditText 
     android:layout_width="match_parent" 
     android:layout_height="wrap_content" 
     android:id="@+id/password" 
     android:hint="PASSWORD" /> 
</android.support.design.widget.TextInputLayout> 

在你的Java文件创建一个对象EdiText代替TextInputLayout并获得值如下。

EdiText mEmail, mPassword; 

    mPassword = (EdiText) findViewById(R.id.password); 
    mEmail = (EdiText) findViewById(R.id.email); 

值由用户在EditText没有TextInputLayout所以你必须从EditText上

我希望它为你工作得值进入！谢谢