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我添加一个可绘制的图像作为标题在列表视图。在活动的情况下,我已经实施了如下。Android添加头到列表视图片段
listView1 = (ListView)findViewById(R.id.listView1);
View header = (View)getLayoutInflater().inflate(R.layout.header, null);
listView1.addHeaderView(header);
不过,现在我想实现同在这样
import android.os.Bundle;
import android.support.v4.app.Fragment;
import android.view.LayoutInflater;
import android.view.View;
import android.view.ViewGroup;
import android.widget.ArrayAdapter;
import android.widget.ListView;
public class ShowFrag1 extends Fragment {
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
Bundle savedInstanceState) {
// Inflate the layout for this fragment
View v=inflater.inflate(R.layout.frag1, container,false);
ListView lv1=(ListView) v.findViewById(R.id.listView1);
Level weather_data[] = new Level[]
{
new Level(R.drawable.s1, "L1", R.drawable.p),
new Level(R.drawable.s2, "L2",R.drawable.p),
new Level(R.drawable.s3, "L3",R.drawable.p),
new Level(R.drawable.s4, "L4",R.drawable.p),
new Level(R.drawable.s6, "L5",R.drawable.p)
};
LevelAdapter adapter = new LevelAdapter(getActivity(),
R.layout.list_item, weather_data);
View header = (View)getLayoutInflater().inflate(R.layout.header, null);
lv1.addHeaderView(header);
lv1.setAdapter(adapter);
return v;
}
}
现在,在这个viewpager片段,我得到一个错误“
的方法getLayoutInflater( Bundle)中的类型片段不是 适用于参数()
“在线
View header = (View)getLayoutInflater().inflate(R.layout.header, null);
如何解决此错误? 感谢
肯定。这取决于你是如何编写R.layout.header – Blackbelt
好的。再次感谢。 –