分配一个数组的值到另一个不合并

Question

我需要第二阵列的某些值追加到所述第一阵列

即，

在第一阵列我创建两个元素，如name和price和从第二个数组获取值，并给它第一阵列

这是我的第一个数组

[ 
    { 
    "id": 8, 
    "user_id": 21, 
    "category_id": 1, 
    "juice_id": 2, 
    "count": "100", 
    "status": "1", 
    "created_at": "2016-02-23 07:12:14", 
    "updated_at": "2016-02-23 07:12:14" 
    }, 
    { 
    "id": 9, 
    "user_id": 21, 
    "category_id": 1, 
    "juice_id": 1, 
    "count": "100", 
    "status": "1", 
    "created_at": "2016-02-23 07:15:47", 
    "updated_at": "2016-02-23 07:15:47" 
    } 
] 

和第二A rray是

{ 
    "1": { 
    "id": 2, 
    "store_id": 1, 
    "category_id": 1, 
    "name": "Cashew Butter Baby", 
    "image": "http://greenhoppingbucket.s3.amazonaws.com/juice/1455719144rebV3iRUlj.png", 
    "description": "Cashew, Butter and Milk", 
    "price": "12.00", 
    "status": 1, 
    "created_at": "2016-02-17 19:56:11", 
    "updated_at": "2016-02-17 19:56:11" 
    }, 
    "2": { 
    "id": 1, 
    "store_id": 1, 
    "category_id": 1, 
    "name": "Kalekolada", 
    "image": "http://greenhoppingbucket.s3.amazonaws.com/juice/1455719105WAVB3SGxT7.png", 
    "description": "Pulp of Kale", 
    "price": "10.00", 
    "status": 1, 
    "created_at": "2016-02-17 19:55:34", 
    "updated_at": "2016-02-17 19:55:34" 
    } 
} 

我的预期结果是

[ 
    { 
    "id": 8, 
    "user_id": 21, 
    "category_id": 1, 
    "juice_id": 2, 
    "count": "100", 
    "status": "1", 
    "created_at": "2016-02-23 07:12:14", 
    "updated_at": "2016-02-23 07:12:14" 
    "name": "Cashew Butter Baby", 
    "price": "12.00", 
    }, 
    { 
    "id": 9, 
    "user_id": 21, 
    "category_id": 1, 
    "juice_id": 1, 
    "count": "100", 
    "status": "1", 
    "created_at": "2016-02-23 07:15:47", 
    "updated_at": "2016-02-23 07:15:47", 
    "name": "Kalekolada", 
    "price": "10.00", 

    } 
] 

我试图做$newArray = array_merge($cartData, $juiceData);

但它只是合并两个数组。

什么是错误，我该怎么做？

Answer 1

下面是合并这些数组的一些代码。你应该有一个共同的索引，但（不同的顺序可能会导致意外的行为）。

<?php 

$a = array(
    array(
     "id" => 8, 
     "user_id" => 21, 
     "category_id" => 1, 
     "juice_id" => 2, 
     "count" => "100", 
     "status" => "1", 
     "created_at" => "2016-02-23 07:12:14", 
     "updated_at" => "2016-02-23 07:12:14" 
    ), 
    array(
     "id" => 9, 
     "user_id" => 21, 
     "category_id" => 1, 
     "juice_id" => 1, 
     "count" => "100", 
     "status" => "1", 
     "created_at" => "2016-02-23 07:15:47", 
     "updated_at" => "2016-02-23 07:15:47" 
    ) 
); 

$b = array(
    array(
     "id" => 2, 
     "store_id" => 1, 
     "category_id" => 1, 
     "name" => "Cashew Butter Baby", 
     "image" => "http://greenhoppingbucket.s3.amazonaws.com/juice/1455719144rebV3iRUlj.png", 
     "description" => "Cashew, Butter and Milk", 
     "price" => "12.00", 
     "status" => 1, 
     "created_at" => "2016-02-17 19:56:11", 
     "updated_at" => "2016-02-17 19:56:11" 
    ), 
    array(
     "id" => 1, 
     "store_id" => 1, 
     "category_id" => 1, 
     "name" => "Kalekolada", 
     "image" => "http://greenhoppingbucket.s3.amazonaws.com/juice/1455719105WAVB3SGxT7.png", 
     "description" => "Pulp of Kale", 
     "price" => "10.00", 
     "status" => 1, 
     "created_at" => "2016-02-17 19:55:34", 
     "updated_at" => "2016-02-17 19:55:34" 
    ) 
); 

// For this to work the arrays need to have the same string keys 
// $merge = array_merge_recursive($a, $b); 

$merge = array(); 
foreach($b as $key => $entry) { 
    if(isset($a[$key])) { 
     $entry += $a[$key]; 
    } 

    $merge[] = $entry; 
} 

var_dump($merge); 

编辑：

在评论新的信息可以给我们这样的：

$categories = array(); 
foreach($b as &$entry) { 
    $categories[$entry['id']] =& $entry; 
} 

$products = array(); 
foreach($a as &$entry) { 
    if(isset($categories[$entry['juice_id']])) { 
     $entry['category'] =& $categories[$entry['juice_id']]; 
    } 

    $products[] =& $entry; 
} 

var_dump($products); 

无需按引用传递他们，但应该节省一些内存。