如何获得一个月范围的滚动年度总计

我试图从一组数据中获得一个滚动的12个月总计，该数据提供给定的月份和年份的分钟数。在很多情况下，我不会有一个月的记录。是否有一种方法可以显示丢失的月份（值为零），然后将其卷起或不显示，但让查询确认这是12个月范围的一部分。下面的查询是我试图使用的，但它只是抓住了以前的记录，并没有考虑到失踪的月份。下面的查询似乎没有与一些总数有一点关系。任何援助将不胜感激。如何获得一个月范围的滚动年度总计

Select year 
     , month 
     , SUM(NVL(minutes, 0)) OVER (order by year,month rows between 11 preceding and current row) as total_minutes 
    from 
    (
    Select * 
    from test_table 
    Order by year, month 
    ) 
    Order by year desc , month desc

这里是创建测试表和数据的sql。

drop table test_table; 
    create table test_table (
     month number(2), 
     year  number(4), 
     minutes number(4,2) 
    ); 

    insert into test_table values (1, 2012, 3); 
    insert into test_table values (2, 2012, 3); 
    insert into test_table values (3, 2012, 3); 
    insert into test_table values (4, 2012, 4); 
    insert into test_table values (5, 2012, 5); 
    insert into test_table values (7, 2012, 5); 
    insert into test_table values (8, 2012, 5); 
    insert into test_table values (9, 2012, 5); 
    insert into test_table values (10, 2012, 4); 
    insert into test_table values (11, 2012, 3); 
    insert into test_table values (12, 2012, 3); 
    insert into test_table values (1, 2011, 3); 
    insert into test_table values (2, 2011, 3); 
    insert into test_table values (5, 2011, 5); 
    insert into test_table values (6, 2011, 5); 
    insert into test_table values (7, 2011, 5); 
    insert into test_table values (8, 2011, 5); 
    insert into test_table values (9, 2011, 5); 
    insert into test_table values (10, 2011, 4); 
    insert into test_table values (11, 2011, 3); 
    insert into test_table values (12, 2011, 3); 
    insert into test_table values (1, 2010, 3); 
    insert into test_table values (2, 2010, 3); 
    insert into test_table values (3, 2010, 3); 
    insert into test_table values (4, 2010, 4); 
    insert into test_table values (5, 2010, 4); 
    insert into test_table values (6, 2010, 5); 
    insert into test_table values (7, 2010, 5); 
    insert into test_table values (10, 2010, 4); 
    insert into test_table values (11, 2010, 4); 
    insert into test_table values (12, 2010, 3); 

    COMMIT;

来源

2012-11-08 Mark Quimby

我确实使用了外连接，但没有给出我需要的滚动12个月范围。我不得不使用窗口子句来让范围和数字出来。

with m_num as(
     select level as mn 
     from dual 
    connect by level <= 12 
    ) 
    select year 
     , mn 
     , minutes 
     , sum(minutes) over(order by year,mn rows between 11 preceding and current row) rt 
    from (select tt.Year 
       , mn.mn 
       , nvl(tt.minutes, 0) minutes 
      from test_table tt 
      partition by (tt.year) 
      right outer join m_num mn 
       on (tt.month = mn.mn) 
     ) 
    order by year desc, mn desc;

来源

2012-11-13 18:07:07

为了填补空白个月partition outer join（Oracle 10g的广告更高）使用下面的查询，如果你真的需要看到那些零，否则你可以保留原来的查询重写SUM功能SUM(NVL(minutes, 0)) OVER (partition by year order by year,month) as total_minutes。

SQL> with m_num as(
    2 select level as mn 
    3  from dual 
    4 connect by level <= 12 
    5 ) 
    6 select year 
    7  , mn 
    8  , minutes 
    9  , sum(minutes) over(partition by year order by year, mn) rt 
10 from (select tt.Year 
11    , mn.mn 
12    , nvl(tt.minutes, 0) minutes 
13   from test_table tt 
14   partition by (tt.year) 
15   right outer join m_num mn 
16    on (tt.month = mn.mn) 
17  ) 
18 order by year desc, mn desc 
19 ; 


YEAR1   MN MINUTES   RT 
----- ---------- ---------- ---------- 
2012   12   3   43 
2012   11   3   40 
2012   10   4   37 
2012   9   5   33 
2012   8   5   28 
2012   7   5   23 
2012   6   0   18 
2012   5   5   18 
2012   4   4   13 
2012   3   3   9 
2012   2   3   6 
2012   1   3   3 
2011   12   3   41 
2011   11   3   38 
2011   10   4   35 
2011   9   5   31 
2011   8   5   26 
2011   7   5   21 
2011   6   5   16 
2011   5   5   11 
2011   4   0   6 
2011   3   0   6 
2011   2   3   6 
2011   1   3   3

来源

2012-11-08 21:54:22

谢谢你的帮助。我不确定如何回复解决方案，因为我不得不为自己的工作做出一些改变。无论如何，我真的很感激它。 –

如何获得一个月范围的滚动年度总计

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