如何从linq列表字典中获取项目

Question

我不太了解LINQ。我发现每一个例子都过分简化，直到我不知道为什么你甚至会使用LINQ，或者太复杂，我需要已经知道LINQ如何工作以理解它。

所以我想知道是否以及如何使用LINQ来做这件事......在这个例子中，假设你有一个玩家类的列表，并且每个类的内部都有一个能力列表。每个技能都有等级要求。你如何使用LINQ为一组特定类选择所有等于或低于某个特定级别的能力？

Giveen这样的数据：

• 的Class1
  • Ability1 - 第1级
  • Ability2 - 等级5
  • Ability3 - 等级9
• 的Class2
  • Ability4 - 1级
  • Ability5 - 第2级
  • Ability6 - 等级6
• Class3的
  • Ability7 - 第2级
  • Ability8 - 等级4
  • Ability9 - 等级6

我想要一个列表所有等级为5级或以下的Class1 & Class3的所有技能。结果应该是{Ability1，Ability2，Ability7，Ability8}。

public class Class1 
{ 

    public class Ability 
    { 
    public string Name { get; set; } 
    public int Level { get; set; } 
    } 

    public class PlayerClass 
    { 
    public string Name { get; set; } 
    public List<Ability> Abilities { get; set; } 
    } 

    public List<PlayerClass> Classes { get; set; } 

    public Class1() 
    { 
    PlayerClass oClass; 

    Classes = new List<PlayerClass>(); 

    oClass = new PlayerClass(); 
    oClass.Name = "Class1"; 
    oClass.Abilities = new List<Ability>(); 
    oClass.Abilities.Add(new Ability() { Name = "Ability1", Level = 1 }); 
    oClass.Abilities.Add(new Ability() { Name = "Ability2", Level = 5 }); 
    oClass.Abilities.Add(new Ability() { Name = "Ability3", Level = 9 }); 
    Classes.Add(oClass); 

    oClass = new PlayerClass(); 
    oClass.Name = "Class2"; 
    oClass.Abilities = new List<Ability>(); 
    oClass.Abilities.Add(new Ability() { Name = "Ability4", Level = 1 }); 
    oClass.Abilities.Add(new Ability() { Name = "Ability5", Level = 2 }); 
    oClass.Abilities.Add(new Ability() { Name = "Ability6", Level = 6 }); 
    Classes.Add(oClass); 

    oClass = new PlayerClass(); 
    oClass.Name = "Class3"; 
    oClass.Abilities = new List<Ability>(); 
    oClass.Abilities.Add(new Ability() { Name = "Ability7", Level = 2 }); 
    oClass.Abilities.Add(new Ability() { Name = "Ability8", Level = 4 }); 
    oClass.Abilities.Add(new Ability() { Name = "Ability9", Level = 6 }); 
    Classes.Add(oClass); 

    IEnumerable<Ability> Abilities = 
        GetAbilitiesForClasses("Class1;Class3".Split(';'), 5); 
    //Abilities should contain Ability1, Ability2, Ability7, Ability8 
    } 

    public IEnumerable<Ability> GetAbilitiesForClasses 
     (string[] asClassNames, int iLevel) 
    { 
    // TODO: Use LINQ to return the abilities for the class names 
      //contained in asClassNames that are at or below level: iLevel 
    return null; 
    } 
} 

Answer 1

public IEnumerable<Ability> GetAbilitiesForClasses(string[] asClassNames, int iLevel) 
{ 
    return Classes 
      .Where(X => asClassNames.Contains(X.Name)) 
      .SelectMany(X => X.Abilities) 
      .Where(X => X.Level <= iLevel) 
      .ToList(); 
} 

Answer 2

如果你只是存储的能力，你可以把它们合并成一个结构，有类的列表，你可以执行LINQ。

例如：

public List<AbilityClass> Abilities { get; set; } 

LINQ：

var level9Abilities = (from a in Abilities 
        where.Level == "Level 9" 
       // where a.Level > 9 (if Level is an int) 
        select a).ToList(); 


foreach (var lvl in level9Abilities) { 
     Console.WriteLine(lvl); 
} 

Answer 3

你可以使用SelectMany，假设：

public class Class 
{ 
    public List<Ability> Abilities { get; set; } 
} 

public class Ability 
{ 
    public string Name { get; set; } 
    public int Level { get; set; } 
} 

使用LINQ：

var classes = new List<Class>() {class1, class3}; 

var output = classes.SelectMany(c => c.Abilities) 
      .Where(a => a.Level <= 5); 

Answer 4

假设您的播放器类是由一个PlayerClass类表示，与IDictionary<string, int>类型的Abilities属性：

List<PlayerClass> classes = ... 
var results = 
    from c in classes 
    where c.Name == "Class1" || c.Name == "Class2" 
    from ab in c.Abilities // ab is of type KeyValuePair<string, int> 
    where ab.Value <= 5 
    select ab.Key; 

但它会更好地界定与Name和Level性质的Ability类;那么Abilities属性将是一个IList<Ability>：

List<PlayerClass> classes = ... 
var results = 
    from c in classes 
    where c.Name == "Class1" || c.Name == "Class2" 
    from ab in c.Abilities 
    where ab.Level <= 5 
    select ab.Name;