我有一个类名为水母谁使用Singleton设计模式:Call对象实例从C++通过脚本调用的函数
jellyfish.h
#ifndef JELLYFISH_H
#define JELLYFISH_H
#include <QHash>
#include <QScriptEngine>
class QScriptValue;
class Jellyfish : public QObject
{
public:
static Jellyfish * getInstance();
static Jellyfish * instance;
private:
Jellyfish();
};
#ifndef
jellyfish.cpp
Jellyfish * Jellyfish::instance = NULL;
Jellyfish * Jellyfish::getInstance()
{
if (!Jellyfish::instance)
{
Jellyfish::instance = new Jellyfish();
}
return Jellyfish::instance;
}
当我在main.cpp并进行测试,我没有错误:
main.cpp
#include <QApplication>
#include "jellyfish.h"
class Jellyfish;
int main(int argc, char *argv[])
{
QApplication app(argc, argv);
Jellyfish *toto = Jellyfish::getInstance();
Jellyfish *toto2 = Jellyfish::getInstance();
Jellyfish *toto3 = Jellyfish::getInstance();
return app.exec();
}
但我想用一些静态方法Jellyfish
外部QScript文件:
jellyfish.h
private:
static QScriptValue set(QScriptContext *context, QScriptEngine *engine);
QScriptEngine *script_engine;
jellyfish.cpp
Jellyfish::Jellyfish()
{
script_engine = new QScriptEngine;
/* ... */
initScriptEngine();
}
void Jellyfish::initScriptEngine()
{
QScriptValue object = script_engine->newQObject(this);
object.setProperty("set", script_engine->newFunction(set));
script_engine->globalObject().setProperty("jellyfish", object);
}
QScriptValue Jellyfish::set(QScriptContext *context, QScriptEngine *engine)
{
// I have to load instance because I am in a static method.
// But this is where the application loop endlessly.
Jellyfish *jellyfish = Jellyfish::getInstance();
return true;
}
而且finaly解析脚本:
jellyfish.set("line_numbers", true);
问题
当我运行应用程序,getInstance()
总是创建一个新的水母实例。但真正的问题是,在调试的输出(qDebug() << "test";
)我可以看到应用程序循环Jellyfish::getInstance();
,直到我得到一个sgmentation fault
。
有人能帮我理解吗?
它会更容易阅读的代码,如果它是连续的,不分裂。那么'set'方法应该是非静态的吗? –
集必须是静态的(如果不是,Qt似乎无法检测到它):'src/jellyfish.cpp:43:64:erreur:没有匹配函数调用'QScriptEngine :: newFunction(<未解析的重载函数类型>)''但是也许我错过了理解(我是Qt新手)。比照http://doc.qt.digia.com/qt/qscriptvalue.html#setProperty –