>>> a="frame 0 rows {3 2 3 3 3 3 2 3 2 3 3 3 2 3 2 3 4 3 3 4 3 2 2 3 3 3 2 2 2 2 3 3 3 2 3 2 3 3 3 3 4 3 4 3 3 3 3 4 3 2 3 3 3 3 2 2 2 4 4 3 3 3 3 3 4 4 4 3 2 4 3 4 3 3 3 4 3 3 4 3 3 4 4 3 3 3 4 4 3 4 3 3 3 3 3 4} columns {2 3 2 3 3 3 4 3 3 2 3 2 2 2 3 2 3 3 2 2 2 3 3 3 3 2 3 3 3 2 3 3 2 2 2 3 3 4 3 3 3 3 3 3 3 3 2 3 3 3 3 4 3 2 3 2 3 3 3 3 3 2 2 3 3 3 3 2 3 3 3 3 3 3 3 3 3 4 3 3 3 3 3 4 3 3 4 3 4 4 4 3 4 4 4 4 4 4 3 3 4 4 3 4 4 4 4 3 3 3 4 4 3 4 4 3 3 4 3 5 5 5 5 4 5 4 4 4}"
>>> import ast
>>> import re
>>> for match in re.finditer("\{([\d ]+)\}",a):
integers=match.groups()[0]
l=ast.literal_eval(integers.replace(" ",","))
print l
(3, 2, 3, 3, 3, 3, 2, 3, 2, 3, 3, 3, 2, 3, 2, 3, 4, 3, 3, 4, 3, 2, 2, 3, 3, 3, 2, 2, 2, 2, 3, 3, 3, 2, 3, 2, 3, 3, 3, 3, 4, 3, 4, 3, 3, 3, 3, 4, 3, 2, 3, 3, 3, 3, 2, 2, 2, 4, 4, 3, 3, 3, 3, 3, 4, 4, 4, 3, 2, 4, 3, 4, 3, 3, 3, 4, 3, 3, 4, 3, 3, 4, 4, 3, 3, 3, 4, 4, 3, 4, 3, 3, 3, 3, 3, 4)
(2, 3, 2, 3, 3, 3, 4, 3, 3, 2, 3, 2, 2, 2, 3, 2, 3, 3, 2, 2, 2, 3, 3, 3, 3, 2, 3, 3, 3, 2, 3, 3, 2, 2, 2, 3, 3, 4, 3, 3, 3, 3, 3, 3, 3, 3, 2, 3, 3, 3, 3, 4, 3, 2, 3, 2, 3, 3, 3, 3, 3, 2, 2, 3, 3, 3, 3, 2, 3, 3, 3, 3, 3, 3, 3, 3, 3, 4, 3, 3, 3, 3, 3, 4, 3, 3, 4, 3, 4, 4, 4, 3, 4, 4, 4, 4, 4, 4, 3, 3, 4, 4, 3, 4, 4, 4, 4, 3, 3, 3, 4, 4, 3, 4, 4, 3, 3, 4, 3, 5, 5, 5, 5, 4, 5, 4, 4, 4)
我从来没有听说过一个分析方法的实际分析中,你问路的字符串。但是,解析该字符串并不困难。这是如何做到这一点。
这不是什么'string.parse()'被设计用于(它在内部使用的String.Format的'部分( )')。请尝试查看're'正则表达式库来代替。 – Amber