通过嵌套数组循环

Question

我有一个输出数组，如下所示。我想遍历数组，以便我可以一次获得一个文件元素。即一次具有其细节的一个图像元素。

我试了很多，但无法做到这一点。

Array 
    (
     [name] => Array 
      (
       [0] => stock-photo-cup-icons-tea-and-coffee-raster-version-109119257.jpg 
       [1] => tea-cup-icon.png 
       [2] => tea.png 
       [3] => stock-vector-vector-black-tea-icons-set-all-white-areas-are-cut-away-from-icons-and-black-areas-merged-81392851.jpg 
      ) 

     [type] => Array 
      (
       [0] => image/jpeg 
       [1] => image/png 
       [2] => image/png 
       [3] => image/jpeg 
      ) 

     [tmp_name] => Array 
      (
       [0] => D:\xampp\tmp\php6BB.tmp 
       [1] => D:\xampp\tmp\php6BC.tmp 
       [2] => D:\xampp\tmp\php6BD.tmp 
       [3] => D:\xampp\tmp\php6BE.tmp 
      ) 

     [error] => Array 
      (
       [0] => 0 
       [1] => 0 
       [2] => 0 
       [3] => 0 
      ) 

     [size] => Array 
      (
       [0] => 30609 
       [1] => 3615 
       [2] => 8966 
       [3] => 23117 
      ) 

    ) 

Answer 1

你的意思是这样吗？

$images = array(); 
foreach($array as $key=>$values){ 

    foreach($values as $no=>$value){ 
     $images[$no][$key] = $value; 
    } 
} 

Answer 2

你可以这样做，虽然它是蹩脚的！

for ($i = 0; $i < count($array["name"]); $i++) 
{ 
    echo $array["name"][$i], $array["type"][$i], $array["size"][$i]; 
} 

注：这仅适用于这种顺序排列的。这不适用于具有关联索引的数组。

Answer 3

你只是通过像数组循环，使

$count = 0; 
foreach ($_FILES['fileField']['name'] as $filename) 
{ 
    $file = $_FILES['fileField']['name'][$count]; 
    $type = $_FILES['fileField']['type'][$count]; 
    $size = $_FILES['fileField']['size'][$count]; 
    $count++; 
} 

Answer 4

我会做这样的事情：

$fileDetais = array(); 

foreach($arr["name"] as $id => $fname) { 
    $fileDetais["name"] = $fname; 
    $fileDetais["type"] = $arr["type"][$id]; 
    $fileDetais["tmp_name"] = $arr["tmp_name"][$id]; 
    $fileDetais["error"] = $arr["error"][$id]; 
    $fileDetais["size"] = $arr["size"][$id]; 
    //now you have all info about one file in $fileDetais 
}