我有以下一段代码,它是一个数组调整功能的实现。这似乎是正确的,但是当我编译程序,我得到了以下错误:指向int的指针引起错误
g++ -Wall -o "resizing_arrays" "resizing_arrays.cpp" (in directory: /home/aristofanis/Desktop/coursera-impl)
resizing_arrays.cpp: In function ‘int main()’:
resizing_arrays.cpp:37: error: invalid initialization of non-const reference of type ‘int*&’ from a temporary of type ‘int*’
resizing_arrays.cpp:7: error: in passing argument 1 of ‘void resize(int*&, int, int, int)’
resizing_arrays.cpp:39: error: invalid initialization of non-const reference of type ‘int*&’ from a temporary of type ‘int*’
resizing_arrays.cpp:7: error: in passing argument 1 of ‘void resize(int*&, int, int, int)’
resizing_arrays.cpp:41: error: invalid initialization of non-const reference of type ‘int*&’ from a temporary of type ‘int*’
resizing_arrays.cpp:7: error: in passing argument 1 of ‘void resize(int*&, int, int, int)’
Compilation failed.
下面是代码:
int N=5;
void resize(int *&arr, int N, int newCap, int initial=0) { // line 7
N = newCap;
int *tmp = new int[ newCap ];
for(int i=0; i<N; ++i) {
tmp[ i ] = arr[ i ];
}
if(newCap > N) {
for(int i=N; i<newCap; ++i) {
tmp[ i ] = initial;
}
}
arr = new int[ newCap ];
for(int i=0; i<newCap; ++i) {
arr[ i ] = tmp[ i ];
}
}
void print(int *arr, int N) {
for(int i=0; i<N; ++i) {
cout << arr[ i ];
if(i != N-1) cout << " ";
}
}
int main() {
int arr[] = { 1, 2, 3, 4, 5 };
print(arr, N);
resize(arr, N, 5, 6); // line 37
print(arr, N);
resize(arr, N, 10, 1); // line 39
print(arr, N);
resize(arr, N, 3); // line 41
print (arr, N);
return 0;
}
谁能帮助我?提前致谢。
'void resize(int *&arr' here remove '&' –
@IonutHulub - 这会破坏函数的目的,即改变指针参数指向的数组大小。 –
没有'*&arr'这样的东西。你认为这是一个指针,所以你不能打电话给它,即使你可以,撤销&的效果,一个是供参考,另一个如果是取消引用。 –