2016-09-14 32 views
0

就像标题所说的,我试图解析一个对象,该对象的关键是一个动态的String。我看了很长一段时间了一些答案,发现1 this,2 this和3 this通过gson解析具有动态密钥的对象

为了您的信息,我还挺新到Java,这是我第一次用JSON数据工作,并解析

JSON响应看起来像这样:

{"Narcos": {"episodes": [{"season": 2, "name": "Episode #2.1", "number": 1}, {"season": 2, "name": "Episode #2.10", "number": 10}, {"season": 2, "name": "Episode #2.2", "number": 2}, {"season": 2, "name": "Episode #2.3", "number": 3}, {"season": 2, "name": "Episode #2.4", "number": 4}, {"season": 2, "name": "Episode #2.5", "number": 5}, {"season": 2, "name": "Episode #2.6", "number": 6}, {"season": 2, "name": "Episode #2.7", "number": 7}, {"season": 2, "name": "Episode #2.8", "number": 8}, {"season": 2, "name": "Episode #2.9", "number": 9}, {"season": 1, "name": "Descenso", "number": 1}, {"season": 1, "name": "Despegue", "number": 10}, {"season": 1, "name": "Explosivos", "number": 6}, {"season": 1, "name": "La Catedral", "number": 9}, {"season": 1, "name": "La Gran Mentira", "number": 8}, {"season": 1, "name": "The Men of Always", "number": 3}, {"season": 1, "name": "The Palace in Flames", "number": 4}, {"season": 1, "name": "The Sword of Sim\u00f3n Bolivar", "number": 2}, {"season": 1, "name": "There Will Be a Future", "number": 5}, {"season": 1, "name": "You Will Cry Tears of Blood", "number": 7}], "year": 2015}} 

动态键,在该示例中 “Narcos”。它基本上是你想要的剧集名称。

我尝试了不同的方法。 对于第一个链接,用于解析的代码如下所示:

ApiTest.class

Type mapType = new TypeToken<Map<String, Serie> >() {}.getType(); // define generic type 

    Map<String, Serie> serie = gson.fromJson(jsonString, mapType); 

Serie.class

public class Serie { 

    private Episodes episodes; 

Episodes.class

public class Episodes { 

    private Episode[] episode; 
    private int year; 

插曲。类

public class Episode { 

    private int season; 
    private String name; 
    private int number; 

当我用第一种方法去,我得到这个错误

Exception in thread "main" com.google.gson.JsonSyntaxException: java.lang.IllegalStateException: Expected BEGIN_OBJECT but was BEGIN_ARRAY at line 1 column 41 path $..episodes 
    at com.google.gson.internal.bind.ReflectiveTypeAdapterFactory$Adapter.read(ReflectiveTypeAdapterFactory.java:224) 
    at com.google.gson.internal.bind.ReflectiveTypeAdapterFactory$1.read(ReflectiveTypeAdapterFactory.java:129) 
    at com.google.gson.internal.bind.ReflectiveTypeAdapterFactory$Adapter.read(ReflectiveTypeAdapterFactory.java:220) 
    at com.google.gson.internal.bind.TypeAdapterRuntimeTypeWrapper.read(TypeAdapterRuntimeTypeWrapper.java:41) 
    at com.google.gson.internal.bind.MapTypeAdapterFactory$Adapter.read(MapTypeAdapterFactory.java:187) 
    at com.google.gson.internal.bind.MapTypeAdapterFactory$Adapter.read(MapTypeAdapterFactory.java:145) 
    at com.google.gson.Gson.fromJson(Gson.java:887) 
    at com.google.gson.Gson.fromJson(Gson.java:852) 
    at com.google.gson.Gson.fromJson(Gson.java:801) 
    at testing.ApiTest.main(ApiTest.java:114) 
Caused by: java.lang.IllegalStateException: Expected BEGIN_OBJECT but was BEGIN_ARRAY at line 1 column 41 path $..episodes 
    at com.google.gson.stream.JsonReader.beginObject(JsonReader.java:385) 
    at com.google.gson.internal.bind.ReflectiveTypeAdapterFactory$Adapter.read(ReflectiveTypeAdapterFactory.java:213) 
    ... 9 more 

当我试图根据其他两个线程来解析数据,我创建了一个响应类是这样的:

PoroResponse.class

public class PoroResponse { 

    private Map<String, Serie> serie; 

,并改变了代码ApiTest.class到:

PoroResponse poro = gson.fromJson(jsonString, PoroResponse.class); 

,并试图获得一个数组通过这个一起工作:

Episode[] episodes = poro.get(poro).getSerie().getEpisodes().getEpisode(); 

我也试图解析它是这样的:

Object o = new Gson().fromJson(json, Object.class); 

但在双方的最后情况下,不是我的意甲对象是NULL或我得到一个LinkedTreeMap与NULL值。

难道有人指着我正确的方向吗?自2天以来,我一直被困在这个问题上,诚实地没有真正的想法如何解决它。

回答

0

也许你可以试试这个: 集类

public class Episode { 

    @SerializedName("season") 
    @Expose 
    private Integer season; 
    @SerializedName("name") 
    @Expose 
    private String name; 
    @SerializedName("number") 
    @Expose 
    private Integer number; 


    public Integer getSeason() { 
     return season; 
    } 


    public void setSeason(Integer season) { 
     this.season = season; 
    } 


    public String getName() { 
     return name; 
    } 


    public void setName(String name) { 
     this.name = name; 
    } 


    public Integer getNumber() { 
     return number; 
    } 


    public void setNumber(Integer number) { 
     this.number = number; 
    } 

} 

然后串行类:

public class Serial { 

    @SerializedName("episodes") 
    @Expose 
    private List<Episode> episodes = new ArrayList<Episode>(); 
    @SerializedName("year") 
    @Expose 
    private Integer year; 

    public List<Episode> getEpisodes() { 
     return episodes; 
    } 


    public void setEpisodes(List<Episode> episodes) { 
     this.episodes = episodes; 
    } 


    public Integer getYear() { 
     return year; 
    } 


    public void setYear(Integer year) { 
     this.year = year; 
    } 

} 

然后生成一个与JSON动态密钥Java对象只要运行这个:

Type type = new TypeToken<Map<String, Serial>>() { 
     }.getType(); 
Map<String, Serial> result = new Gson() 
       .fromJson(new InputStreamReader(new ByteArrayInputStream(jsonString.getBytes())), type); 

要获得Narcos的系列信息,您需要编写这个信息:

Serial narcosSerial = result.get("Narcos"); 
+0

感谢您的意见。我应该补充说Narcos是动态的关键。它根据对API的请求而改变。所以它总是你要求的节目的名字。 这是API的URL,如果它可能有帮助。 我将编辑我的问题,使其更清楚一点。 – Tagman

+0

@Tagman我编辑了我的答案。请看看 – user3662708

+0

非常感谢。这正是我所期待的。我仍然在试图弄清为什么我只需要这两个班。但代码就像我想要的那样工作。 – Tagman