仅查找最大数据记录

Question

我有以下查询

select ROW_NUMBER() over(order by [emp_no]) as RowId, 
     emp_no, 
     pc_ip, 
     count(1) as count into #tmp 
    from ip_track 
group by emp_no, pc_ip 

select * 
    from #tmp 
    where emp_no in ('e44920','e39787') 

，我已经为一个例子只选择了2员工记录.. 此查询给我下面的数据

RowId emp_no pc_ip count 
790033 E39787 172.29.22.36 1 
790034 E39787 172.29.23.48 3 
790035 E39787 172.29.23.49 37 
790036 E39787 172.29.23.50 724 
790037 E39787 172.29.23.53 18 
790038 E39787 172.29.23.17 48 
790039 E39787 172.29.24.38 325 
790040 E39787 172.29.31.183 1 
790041 E39787 172.29.23.45 7 
790042 E39787 172.29.23.18 5 
790043 E39787 172.29.23.34 1 
790044 E39787 172.29.22.31 1 
790045 E39787 172.29.23.40 2 
790046 E39787 172.29.23.55 56 
790047 E39787 172.29.22.43 1 
790048 E39787 172.29.23.10 2 
790049 E39787 172.29.23.58 6 
790050 E39787 172.29.23.54 3 
790051 E39787 172.29.21.36 25 
790052 E39787 172.29.23.43 11 
790053 E39787 172.29.24.121 4 
846618 E44920 172.29.24.34 1 
846619 E44920 172.29.23.55 1292 
846620 E44920 172.29.23.34 12 
846621 E44920 172.29.23.10 1 
846622 E44920 172.29.23.58 2 
846623 E44920 172.29.23.40 11 
846624 E44920 172.29.23.48 39 
846625 E44920 172.29.23.45 1 
846626 E44920 172.29.23.50 8 
846627 E44920 172.29.23.53 2 
846628 E44920 172.29.23.17 7 
846629 E44920 172.29.24.38 31 
846630 E44920 172.29.21.36 10 
846631 E44920 172.29.23.43 14 
846632 E44920 172.29.23.54 15 

现在我想从不同的雇员这个记录中找到最大数据，以便输出将如下所示

RowId emp_no pc_ip   count 

790036 E39787 172.29.23.50 724 
846619 E44920 172.29.23.55 1292 

我想只得到最大计数数据..我可以这样做，请回复..在此先感谢。

Answer 1

select * 
from #tmp B 
where emp_no in ('e44920','e39787') 
and 
[Count]=(Select Max([Count] from #tmp A where A.emp_no =B.emp_no) 

Answer 2

select RowId,emp_no,pc_ip from 
( 
select RowId,emp_no,pc_ip,count, row_number() over(partition by emp_no order by count desc) chk 
    from #tmp 
    where emp_no in ('e44920','e39787') 
) a 
where chk = 1