MySQLdb Python查询

Question

我正在尝试将SQL查询从PHP转换为MySQLdb for Python。

以下是PHP代码：

$query = " 
     select 
      `ip_address`.`address`, 
      `interface`.`name`, 
      `equipment`.`dns_hostname`,`interface`.`vrf_id` 
     from 
      `equipment` `equipment` 
       inner join `tm_se_equipment` `tm_se_equipment` 
       on `equipment`.`id` = `tm_se_equipment`.`equipment_id` 
        inner join `interface` `interface` 
        on `interface`.`equipment_id` = `equipment`.`id` 
         inner join `ip_address` `ip_address` 
         on `ip_address`.`if_id` = `interface`.`id` 
     where 
      (`ip_address`.`address` = '$ip_address') 
    "; 

我试图像这样翻译，但它没有工作，我获取唯一的结果就是()：

ip_address = ipaddr.IPAddress(linknet) 
linknet = "1.1.1.1" 

cursor.execute("""SELECT `ip_address`.`address`, `interface`.`name`, `equipment`.`dns_hostname`, `interface`.`vrf_id` FROM `equipment` `equipment` INNER JOIN `tm_se_equipment` `tm_se_equipment` ON `equipment`.`id` = `tm_se_equipment`.`equipment_id` INNER JOIN `interface` `interface` ON `interface`.`equipment_id` = `equipment`.`id` INNER JOIN `ip_address` `ip_address` ON `ip_address`.`if_id` = `interface`.`id` WHERE `ip_address`.`address` = %s""", (ip_address,)) 

Answer 1

试试这个：

cursor.execute("""SELECT `ip_address`.`address`, `interface`.`name`, `equipment`.`dns_hostname`, `interface`.`vrf_id` FROM `equipment` `equipment` INNER JOIN `tm_se_equipment` `tm_se_equipment` ON `equipment`.`id` = `tm_se_equipment`.`equipment_id` INNER JOIN `interface` `interface` ON `interface`.`equipment_id` = `equipment`.`id` INNER JOIN `ip_address` `ip_address` ON `ip_address`.`if_id` = `interface`.`id` WHERE `ip_address`.`address` = '%s'""" % ip_address) 

或者如果你试图将ip地址作为参数来执行函数，你需要使用“？”而不是“％”