2016-01-20 140 views
0

请原谅我,如果我问一些愚蠢的东西,我是一个新手在这里。我需要在我的Java应用程序中实施OAuth以对launchpad.net API进行身份验证。 documentation指定使用三个参数启动令牌请求:oauth_consumer_key例如(我的应用程序的名称),oauth_signature_method例如“PLAINTEXT”和oauth_signature,例如字符串“&”。我意识到大多数OAuth库要求我已经从OAuth提供者(例如Twitter发布的)中获得了消费者密钥和消费者ID /密钥,并且大多数示例都以这种方式组织。但是,launchpad.net只有在发出请求令牌(他们不使用第三方提供者)之后才会发出这些参数。我该如何继续?我现在在尝试一些引发错误的库后仍然陷入困境。非常感谢任何有用的信息。正式的launchpad库在python中。Oauth令牌请求提供者凭据发布前

我最初的代码如下:

public class Quicky { 

    public static void main(String[] args) throws Exception { 
     CloseableHttpClient httpclient = HttpClients.createDefault(); 
     try { 
      HttpGet httpGet = new HttpGet("https://launchpad.net/+request-token"); 
      CloseableHttpResponse response1 = httpclient.execute(httpGet); 
try { 
       System.out.println("Your current GET request status:" + response1.getStatusLine()); 
       HttpEntity entity1 = response1.getEntity(); 
    EntityUtils.consume(entity1); 
      } finally { 
       response1.close(); 
      } 

      HttpRequest request; 
      HttpPost httpPost = new HttpPost("https://launchpad.net/+request-token"); 
      PostMethod poster = new PostMethod(); 
      List <NameValuePair> postParams = new ArrayList <NameValuePair>(); 
      postParams.add(new BasicNameValuePair("oauth_customer_key", "XXXX")); 
      postParams.add(new BasicNameValuePair("oauth_signature_method", "PLAINTEXT")); 
      postParams.add(new BasicNameValuePair("oauth_signature", "&")); 
    httpPost.setEntity(new UrlEncodedFormEntity(postParams, "utf-8")); 
//   httpPost.setEntity(entity1); 
      httpclient.execute(httpPost); 

      HttpParameters requestParams = (HttpParameters) postParams; 
      CloseableHttpResponse response2 = httpclient.execute(httpPost); 
      try { 
       System.out.println("Your current POST request status:" + response2.getStatusLine()); 
       HttpEntity entity2 = response2.getEntity(); 
       // do something useful with the response body 
       // and ensure it is fully consumed 
       EntityUtils.consume(entity2); 
      } finally { 
       response2.close(); 
      } 
     } finally { 
      httpclient.close(); 
     } 
    } 

} 
+0

显示你到目前为止所尝试过的,并具体。你有一个合理的问题,但它可能会被关闭,因为你没有提供足够的信息。 –

+0

@MadPhysicist感谢您的有用观察。我已经添加了我的代码。我跑步时会得到401。 – SyCode

回答

0

一些研究和代码重新分解后,我终于解决了这个问题的错误消息。正确的代码在下面,也许它可能对那里的人有用。

public class LaunchPadTokenRetriever { 

    public static void main(String[] args) throws ClientProtocolException,  IOException{ 

    CloseableHttpClient httpclient = HttpClients.createDefault(); 

    HttpPost httpPost = new HttpPost("https://launchpad.net/+request-token"); 
    httpPost.addHeader("Content-Type", "application/x-www-form-urlencoded"); 

    List <NameValuePair> urlParams = new ArrayList <NameValuePair>(); 
    urlParams.add(new BasicNameValuePair("oauth_signature", "&")); 
    urlParams.add(new BasicNameValuePair("oauth_consumer_key", "tester")); 
    urlParams.add(new BasicNameValuePair("oauth_signature_method", "PLAINTEXT")); 
    httpPost.setEntity(new UrlEncodedFormEntity(urlParams)); 
    CloseableHttpResponse response = httpclient.execute(httpPost); 
    System.out.println(response); 

    try { 
     System.out.println(response.getStatusLine()); 
     HttpEntity entity = response.getEntity(); 
     ResponseHandler<String> responseHandler = new BasicResponseHandler(); 
     String responseBody = httpclient.execute(httpPost, responseHandler); 
     System.out.println("Initial credentials ---> "+ responseBody); 
     System.out.println();  
     String getresponse = responseBody; 

     EntityUtils.consume(entity); 
    } finally { 
     response.close(); 
    } 
    } 

}