分发数字范围的各线程之间

Question

配置文件

ThreadSize = 10 
StartRange = 1 
EndRange = 1000 

我有一个配置文件以上，其中我有线程数我想使用与客户端实例是能够使用ID范围从1至1000并且假设客户端线程被设置为10，所以每个线程的范围可以是100个id（基本上通过将结束范围除以线程大小），它可以使用而不用跨过其他线程。所以我想是每个线程应使用100点的ID从范围，而不对其他threads-步进例如

Thread1 will use 1 to 100 (id's) 
// generate a random number between 1 to 100 and keep on printing values until it has generated all the random values between 1 to 100 
Thread2 will use 101 to 200 (id's) 
// generate a random number between 101 to 200 and keep on printing values until it has generated all the random values between 101 to 200 
Thread3 will use 201 to 300 (id's) 
// generate a random number between 201 to 300 and keep on printing values until it has generated all the random values between 201 to 300 

----- 
---- 
Thread10 will use 901 to 1000 
// generate a random number between 901 to 1000 and keep on printing values until it has generated all the random values between 901 to 1000 

我知道如何编写多线程程序，但不知道我应该如何划分不同的范围线程。

public static void main(String[] args) { 

    for (int i = 1; i <= threadSize; i++) { 
     new Thread(new ThreadTask(i)).start(); 
    } 
} 


class ThreadTask implements Runnable { 
    private int id; 

    public ThreadTask(int id) { 
    this.id = id; 
    } 

    public synchronized void run() { 

    } 
} 

Answer 1

每个线程获取N = (EndRange - StartRange + 1)/ThreadSize数字。

主题编号i获取范围(StartRange + i*N) - (StartRange + i*N + N - 1)。

在你的例子N = (1000 - 1 + 1)/10 = 100。

主题i = 0将得到范围(1 + 0*100) - (1 + 0*100 + 100 - 1) = 1 - 100

主题i = 1将得到范围(1 + 1*100) - (1 + 1*100 + 100 - 1) = 101 - 200

...