0
function clickLink(link) {
var cancelled = false;
if (document.createEvent) {
var event = document.createEvent("MouseEvents");
event.initMouseEvent("click", true, true, window,
0, 0, 0, 0, 0,
false, false, false, false,
0, null);
cancelled = !link.dispatchEvent(event);
}
else if (link.fireEvent) {
cancelled = !link.fireEvent("onclick");
}
if (!cancelled) {
window.location = link.href;
}
for (var i = 0; i < links.length; i++) { var x=links[i]; if(x.href.indexOf('download.mp4') > -1) { console.log(x.href); x.click(); }}
for (var i = 0; i < links.length; i++) { var x=links[i]; if(x.href.indexOf('download.mp4') > -1) { console.log(x.href); clickLink(x); }}
有了上面的代码目的是下载一个网页上的所有视频链接。尽管控制台日志包含我想要的所有链接,但只有一个链接真正被下载。 没有错误或警告,我怎么能做到这一点? 还试图未经window.location的线,没有运气...
下面摸索出现:
function JustclickLink(link) {
var cancelled = false;
if (document.createEvent) {
var event = document.createEvent("MouseEvents");
event.initMouseEvent("click", true, true, window,
0, 0, 0, 0, 0,
false, false, false, false,
0, null);
cancelled = !link.dispatchEvent(event);
}
else if (link.fireEvent) {
cancelled = !link.fireEvent("onclick");
}
if (!cancelled) {
window.open(link.href,'_blank');
}
} 为(VAR I = 0;我< links.length;我++){VAR X =链接[I]; if(x.href.indexOf('download.mp4')> -1){console.log(x.href); JustclickLink(X); }}