我有一个值列表(天气数据),编写列表的人在没有值的情况下使用值“9999”进行报告。我导入的文本文件,并使用下面的代码来获取数据,并对其进行编辑:双打列表打印字符串
import java.io.*;
import java.util.*;
public class weatherData {
public static void main(String[] args)
throws FileNotFoundException{
Scanner input = new Scanner(new File("PortlandWeather2011.txt"));
processData(input);
}
public static void processData (Scanner stats){
String head = stats.nextLine();
String head2 = stats.nextLine();
System.out.println(head);
System.out.println(head2);
while(stats.hasNextLine()){
String dataLine = stats.nextLine();
Scanner dataScan = new Scanner(dataLine);
String station = null;
String date = null;
double prcp = 0;
double snow = 0;
double snwd = 0;
double tmax = 0;
double tmin = 0;
while(dataScan.hasNext()){
station = dataScan.next();
date = dataScan.next();
prcp = dataScan.nextInt();
snow = dataScan.nextInt();
snwd = dataScan.nextInt();
tmax = dataScan.nextInt();
tmin = dataScan.nextInt();
System.out.printf("%17s %10s %8.1f %8.1f %8.1f %8.1f %8.1f \n", station, date(date), prcp(prcp), inch(snow), inch(snwd), temp(tmax), temp(tmin));
}
}
}
public static String date(String theDate){
String dateData = theDate;
String a = dateData.substring(4,6);
String b = dateData.substring(6,8);
String c = dateData.substring(0,4);
String finalDate = a + "/" + b + "/" + c;
return finalDate;
}
public static double prcp(double thePrcp){
double a = (thePrcp * 0.1)/25.4;
return a;
}
public static double inch(double theInch){
double a = theInch/25.4;
if(theInch == 9999){
a = 9999;
}
return a;
}
public static double temp(double theTemp){
double a = ((0.10 * theTemp) * 9/5 + 32);
return a;
}
}
我有走的是价值和检查所有的时间“9999”的问题出现了,并打印出“ ----”。我不知道如何获取double类型的值,并打印出一个String。
这段代码取值9999,并且不做任何事情。这是我的问题所在:
public static double inch(double theInch){
double a = theInch/25.4;
if(theInch == 9999){
a = "----";
}
return a;
}
如果我在这个问题中提供了大量信息,我很抱歉。如果你需要我澄清就问。谢谢你的帮助!
您有什么错误? – user962206
@ user962206呃......希望你知道最后一段代码片段中有什么问题。如果你不......呃... ... – Doorknob