内部加入cakephp 3

以及我需要做一个内部连接fron 2表，但总是获得相同的错误，我发送这个邮递员，我试图接受id与这两个表执行内部连接，现在用这个例子从documentation 内部加入cakephp 3

{ 
    "message": "Failed calling Cake\\ORM\\Query::jsonSerialize()", 
    "url": "https://stackoverflow.com/users/userdata", 
    "code": 500 
}

和错误日志：

2017-04-20 01:50:24 Error: [Exception] Failed calling Cake\ORM\Query::jsonSerialize() 
Request URL: /users/userdata 
Stack Trace: 
#0 C:\xampp\htdocs\dekma_backend\vendor\cakephp\cakephp\src\View\JsonView.php(0): json_encode() 
#1 C:\xampp\htdocs\dekma_backend\vendor\cakephp\cakephp\src\View\SerializedView.php(98): Cake\View\JsonView->_serialize(Array) 
#2 C:\xampp\htdocs\dekma_backend\vendor\cakephp\cakephp\src\View\JsonView.php(107): Cake\View\SerializedView->render(NULL, NULL) 
#3 C:\xampp\htdocs\dekma_backend\vendor\cakephp\cakephp\src\Controller\Controller.php(623): Cake\View\JsonView->render(NULL, NULL) 
#4 C:\xampp\htdocs\dekma_backend\vendor\cakephp\cakephp\src\Http\ActionDispatcher.php(125): Cake\Controller\Controller->render() 
#5 C:\xampp\htdocs\dekma_backend\vendor\cakephp\cakephp\src\Http\ActionDispatcher.php(93): Cake\Http\ActionDispatcher->_invoke(Object(App\Controller\UsersController)) 
#6 C:\xampp\htdocs\dekma_backend\vendor\cakephp\cakephp\src\Http\BaseApplication.php(78): Cake\Http\ActionDispatcher->dispatch(Object(Cake\Http\ServerRequest), Object(Cake\Http\Response)) 
#7 C:\xampp\htdocs\dekma_backend\vendor\cakephp\cakephp\src\Http\Runner.php(65): Cake\Http\BaseApplication->__invoke(Object(Cake\Http\ServerRequest), Object(Cake\Http\Response), Object(Cake\Http\Runner)) 
#8 C:\xampp\htdocs\dekma_backend\vendor\ozee31\cakephp-cors\src\Routing\Middleware\CorsMiddleware.php(28): Cake\Http\Runner->__invoke(Object(Cake\Http\ServerRequest), Object(Cake\Http\Response)) 
#9 C:\xampp\htdocs\dekma_backend\vendor\cakephp\cakephp\src\Http\Runner.php(65): Cors\Routing\Middleware\CorsMiddleware->__invoke(Object(Cake\Http\ServerRequest), Object(Cake\Http\Response), Object(Cake\Http\Runner)) 
#10 C:\xampp\htdocs\dekma_backend\vendor\cakephp\cakephp\src\Routing\Middleware\RoutingMiddleware.php(59): Cake\Http\Runner->__invoke(Object(Cake\Http\ServerRequest), Object(Cake\Http\Response)) 
#11 C:\xampp\htdocs\dekma_backend\vendor\cakephp\cakephp\src\Http\Runner.php(65): Cake\Routing\Middleware\RoutingMiddleware->__invoke(Object(Cake\Http\ServerRequest), Object(Cake\Http\Response), Object(Cake\Http\Runner)) 
#12 C:\xampp\htdocs\dekma_backend\vendor\cakephp\cakephp\src\Routing\Middleware\AssetMiddleware.php(88): Cake\Http\Runner->__invoke(Object(Cake\Http\ServerRequest), Object(Cake\Http\Response)) 
#13 C:\xampp\htdocs\dekma_backend\vendor\cakephp\cakephp\src\Http\Runner.php(65): Cake\Routing\Middleware\AssetMiddleware->__invoke(Object(Cake\Http\ServerRequest), Object(Cake\Http\Response), Object(Cake\Http\Runner)) 
#14 C:\xampp\htdocs\dekma_backend\vendor\cakephp\cakephp\src\Error\Middleware\ErrorHandlerMiddleware.php(92): Cake\Http\Runner->__invoke(Object(Cake\Http\ServerRequest), Object(Cake\Http\Response)) 
#15 C:\xampp\htdocs\dekma_backend\vendor\cakephp\cakephp\src\Http\Runner.php(65): Cake\Error\Middleware\ErrorHandlerMiddleware->__invoke(Object(Cake\Http\ServerRequest), Object(Cake\Http\Response), Object(Cake\Http\Runner)) 
#16 C:\xampp\htdocs\dekma_backend\vendor\cakephp\cakephp\src\Http\Runner.php(51): Cake\Http\Runner->__invoke(Object(Cake\Http\ServerRequest), Object(Cake\Http\Response)) 
#17 C:\xampp\htdocs\dekma_backend\vendor\cakephp\cakephp\src\Http\Server.php(80): Cake\Http\Runner->run(Object(Cake\Http\MiddlewareQueue), Object(Cake\Http\ServerRequest), Object(Cake\Http\Response)) 
#18 C:\xampp\htdocs\dekma_backend\webroot\index.php(38): Cake\Http\Server->run() 
#19 {main}

控制器：

public function userdata() 
    { 

     $query = $this->Users->find('all') 
      ->join([ 
       'subsection' => [ 
        'table' => 'subsections', 
        'type' => 'inner', 
        'conditions' => 'users.subsection_id = subsections.id', 
       ], 
       'city' => [ 
        'table' => 'cities', 
        'type' => 'INNER', 
        'conditions' => 'users.city_id = cities.id', 
       ] 
      ]); 

     //$user = $this->Users->get($id); 

     $this->set([ 
      'success' => true, 
      'data' => $query, 
      '_serialize' => ['success', 'data'] 
     ]); 
    }

Mysql的，我需要的是这样的：

SELECT * FROM mydb.users 
INNER JOIN subsections on users.subsection_id = subsections.id 
INNER JOIN cities on users.city_id = cities.id;

我改变的PHP版本号的工作，但选择不为表中各部分和城市工作

来源

2017-04-20 CoolLife

你能检查你的最终的sql命令吗？你是否也在控制器中包含了指定的命名空间/路径？ – marmeladze

当我从postman发送json数据时，我无法检查sql命令，这是一个问题。 – CoolLife

不，我只是想让你检查一下你的sql控制台中的查询，看它是否有错误或没有？ – marmeladze

请这样的询问之后添加->toArray();：

$query = $this->Users->find('all') 
      ->join([ 
       'subsection' => [ 
        'table' => 'subsections', 
        'type' => 'inner', 
        'conditions' => 'users.subsection_id = subsections.id', 
       ], 
       'city' => [ 
        'table' => 'cities', 
        'type' => 'INNER', 
        'conditions' => 'users.city_id = cities.id', 
       ] 
      ])->toArray();

并检查它。我希望它能帮助你。

来源

2017-04-20 09:12:46 First

内部加入cakephp 3

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