使用xpath选择特定的xnode

<segmentFlightRef> 
    <referencingDetail> 
     <refQualifier>S</refQualifier> 
     <refNumber>4</refNumber> 
    </referencingDetail> 
    <referencingDetail> 
     <refQualifier>S</refQualifier> 
     <refNumber>1</refNumber> 
    </referencingDetail> 
</segmentFlightRef> 
<segmentFlightRef> 
    <referencingDetail> 
     <refQualifier>S</refQualifier> 
     <refNumber>5</refNumber> 
    </referencingDetail> 
    <referencingDetail> 
     <refQualifier>S</refQualifier> 
     <refNumber>1</refNumber> 
    </referencingDetail> 
</segmentFlightRef> 
    <segmentFlightRef> 
    <referencingDetail> 
     <refQualifier>S</refQualifier> 
     <refNumber>1</refNumber> 
    </referencingDetail> 
    <referencingDetail> 
     <refQualifier>S</refQualifier> 
     <refNumber>5</refNumber> 
    </referencingDetail> 
</segmentFlightRef>

在上面的xml我想要“segmentFlightRef”标记的子节点“refNumber”具有值“5”和“1”。和顺序必须考虑，所以我需要它的子节点值5和1 sequencially 请帮我感谢事先只在一个节点使用xpath选择特定的xnode

来源

2014-02-21 Brijesh Gandhi

的XPath：

//segmentFlightRef[referencingDetail[following-sibling::referencingDetail/refNumber = 1]/refNumber = 5]

来源

2014-02-21 10:43:51 dirkk

thanx为您的答案，但我编辑了我的问题。我只需要单个节点。请再次参考 –

@BrijeshGandhi更新了我的答案。 – dirkk

非常感谢您 –

的XPath：

//segmentFlightRef[./referencingDetail[./refNumber[text()="5"] and ./following-sibling::referencingDetail[./refNumber[text()="1"]]]]

说明：

//segmentFlightRef[./referencingDetail[...]]

选择<segmentFlightRef>为元素的子元素<referencingDetail>与标准如下：

标准我：

./refNumber[text()="5"]

有子元素<refNumber>与内部文本等于"5"。

标准II：

and ./following-sibling::referencingDetail[./refNumber[text()="1"]]

，并与标准的下一个/同级节点<referencingDetail>：具有内部文本子元素<refNumber>等于"1"。

来源

2014-02-21 11:16:23 har07

对于您的代码段，有些事情是不必要的和/或令人困惑的。因为您已经在正确的上下文中，因此不需要点构造'。/'。另外，你不必使用'text（）'，因为它会被自动雾化（并且'text（）'可以显着减慢你的代码的速度） – dirkk

使用xpath选择特定的xnode

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