我目前工作的一个项目,用户可以保存笔记片段中有自己的小用户区。笨数据库检查
我想知道如何将我检查,如果一个项目的ID存在,例如,如果用户访问 http://mysite.com/view/1并有1记片断它会显示所有与一个ID的数据。现在,如果用户要更改网址以允许说1000,该ID不存在,并且该视图只是错误。
我希望能够将其重定向到一个错误消息的某一页“片段不存在”等
继承人是我迄今(我现在已经有一个条件语句在这里检查片段是私有的,那么如果是重定向到/ publicsnippets)
控制器:
class Publicsnippets extends CI_Controller {
function __construct()
{
parent::__construct();
if (!$this->tank_auth->is_logged_in()) {
redirect('/login/');
}
$this->load->model('dashboard_model');
$this->data['user_id'] = $this->tank_auth->get_user_id();
$this->data['username']= $this->tank_auth->get_username();
}
public function index()
{
$this->data['public_snippets'] = $this->dashboard_model->public_snippets();
$this->load->view('dashboard/public_snippets', $this->data);
}
public function view($snippet_id)
{
$snippet = $this->dashboard_model->get_snippet($snippet_id);
if ($snippet['state'] === 'private')
{
$this->session->set_flashdata('message', "<b style=\"color:red;\">You are not allowed to view this snippet!</b>");
redirect('/publicsnippets');
} else {
$this->data['snippet'] = $snippet;
}
$this->load->view('dashboard/view_public_snippet', $this->data);
}
}
型号:
class Dashboard_model extends CI_Model {
public function public_snippets()
{
$this->db->select('id, title, description, tags, author, date_submitted');
$query = $this->db->get_where('snippets', array('state' => 'public'));
return $query->result_array();
}
public function private_snippets()
{
$this->db->select('id, title, description, tags, author, date_submitted');
$query = $this->db->get_where('snippets', array('user_id' => $this->tank_auth->get_user_id()));
return $query->result_array();
}
public function add_snippet($data)
{
$this->db->insert('snippets', $data);
$id = $this->db->insert_id();
return (isset($id)) ? $id : FALSE;
}
public function get_snippet($snippet_id) {
$query = $this->db->get_where('snippets', array('id' => $snippet_id));
return $query->row_array();
}
public function update_snippet($snippet_id, $data)
{
$this->db->where('id', $snippet_id);
$this->db->update('snippets', $data);
}
public function delete_snippet($snippet_id)
{
$this->db->where('id', $snippet_id);
$this->db->delete('snippets');
}
}
查看:
<h3>Description</h3>
<p><?php echo $snippet['description']; ?></p>
<h3>Tags</h3>
<p><?php echo $snippet['tags']; ?></p>
<h3>Date Submitted</h3>
<p><?php echo $snippet['date_submitted']; ?></p>
<h3>Snippet</h3></pre>
<pre class="prettyprint"><?php echo $snippet['code_snippet']; ?></pre>
非常感谢工作就像一个魅力! – jackthedev 2013-04-29 20:38:47