Java如何计算3个保龄球分数的平均值

-3

我正在编写一个程序，计算并显示用户输入的每个投球手的平均保龄球分数。我在计算3分数的平均数时遇到了麻烦，现在我认为它是计算分数的总和。我如何使它所以它计算分数的平均Java如何计算3个保龄球分数的平均值

public static void main (String [] args) 
{ 



//local constants 


    //local variables 
    String bowler = ""; 
    int total = 0; 
    int average = 0; 
    int score1 = 0; 
    int score2 = 0; 
    int score3 = 0; 

    /******************** Start main method *****************/ 

    //Enter in the name of the first bowler 
    System.out.print(setLeft(40," Input First Bowler or stop to Quit: ")); 
    bowler = Keyboard.readString(); 

    //Enter While loop if input isn't q 
    while(!bowler.equals("stop")) 
    { 

     System.out.print(setLeft(40," 1st Bowling Score:")); 
     score1 = Keyboard.readInt(); 
     System.out.print(setLeft(40," 2nd Bowling Score:")); 
     score2 = Keyboard.readInt(); 
     System.out.print(setLeft(40," 3rd Bowling Score:")); 
     score3 = Keyboard.readInt(); 
     if(score1 >= 0 && score1 <= 300 && score2 >= 0 && score2 <= 300 && score3 >= 0 && score3 <= 300) 
     { 
      total += score1; 
      total += score2; 
      total += score3; 
      System.out.println(setLeft(41,"Total: ")+ total); 
      average = score1 + score2 + score3/3; 
      System.out.println(setLeft(41,"Average: ") + average); 


     } 
     else 
     { 
      System.out.println(setLeft(40,"Error")); 

     }

来源

2017-10-10 user8723490

输入和输出你得到截至目前什么平均？ – notyou

如果我为每个分数输入20，它表示平均值是46，不知道为什么 – user8723490

提示：在代码中大量地使用圆括号。 –

Java的数学运算符遵守标准的数学优先级，所以它的

int average = score1 + score2 + (score3/3);

但是， [R意向很可能

int average = (score1 + score2 + score3)/3;

最后，您很可能希望进行这样的计算中double（或float）运算，否则将被舍去

double average = (double)(score1 + score2 + score3)/3;

来源

2017-10-10 20:56:55 Izruo

+1指出整数除法，虽然问题也有'平均'作为'int'，所以也应该可能是'双' – SteveR

分工（/）操作符比加法运算符（+）的优先级高，所以你需要将之前为封装与支架的总和：

average = (score1 + score2 + score3)/3; 
// Here --^------------------------^

来源

2017-10-10 20:56:16 Mureinik

Java如何计算3个保龄球分数的平均值

回答

相关问题