因此,我使用此方法获取了两个日期之间的差异。将年份或月份转换为天数,PHP
$diff = abs(strtotime($date2) - strtotime($date1));
$years = floor($diff/(365*60*60*24));
$months = floor(($diff - $years * 365*60*60*24)/(30*60*60*24));
$days = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));
现在,让我们说我想将年份和月份转换为天。我怎么做?
你应该看看这个:http://de2.php.net/DateTime要容易得多。 – looper
重复:http://stackoverflow.com/questions/4233605/elegant-way-to-get-the-count-of-months-between-two-dates – GBD