我已经阅读了大量类似的问题,但没有找到答案。我正在使用Visual Studio 2010并提升1.47。派生对象的boost序列化不调用派生的序列化()
下面的代码,它是完整的,可编译:
#include "stdafx.h"
#include <string>
#include <sstream>
#include <boost/archive/text_oarchive.hpp>
#include <boost/archive/text_iarchive.hpp>
#include <boost/serialization/export.hpp>
using namespace std;
class BaseObject
{
public:
BaseObject(void) { };
virtual ~BaseObject(void) { };
template<class Archive>
void serialize(Archive &ar, const unsigned int version)
{ /* nothing happens here */ };
};
class DerivedObject : public BaseObject
{
public:
string text;
public:
DerivedObject(void) { };
~DerivedObject(void) { };
template<class Archive>
void serialize(Archive &ar, const unsigned int version)
{
ar & text;
};
};
BOOST_CLASS_EXPORT(DerivedObject)
int _tmain(int argc, _TCHAR* argv[])
{
DerivedObject der;
der.text = "Testing!";
std::ostringstream os;
boost::archive::text_oarchive oa(os);
oa.register_type<DerivedObject>();
// I made a DerivedObject, but I'm casting it to a BaseObject
// as the serialization code should not have to know what type it is
BaseObject *base = &der;
// now serialize it
oa << *base;
printf("serialized: %s\r\n",os.str().c_str());
return (0);
}
你可以看到它的真正简单,我添加了是应该确保DerivdObject ::序列化BOOST_CLASS_EXPORT和oa.register_type魔术()被称为即使它不是一个虚拟的方法..但仍然只调用BaseObject中的serialize()。一个特定于Visual C++的问题?请指教?
不应该将'BaseObject :: serialize'标记为'virtual'? – Nick 2012-03-15 10:45:25
不,它是一个模板,它不可能 – 2012-03-15 10:50:41
好点 - 没有注意到模板位! – Nick 2012-03-15 10:53:46