如何在foreach循环检查$ _ POST变量有多个阵列

Question

我使用这个代码来过滤多个字段

$fields = array('ageid', 'heightid', 'waistid'); //database fields 
    $txtfields = array('txtagefrom', 'txtheightfrom', 'txtwaistfrom'); //from range 
    $txttofields = array('txtageto', 'txtheightto', 'txtwaistto'); // To Range 


$conditions = array(); 
foreach (array_map(NULL, $fields, $txtfields, $txttofields) as $x) { 

    list($fields, $txtfields, $txttofields) = $x; 
echo "'" . $fields . "' between '" . $txtfields . "' And '" . $txttofields . "'"; 
} 

，但我坚持，如果某些字段为空，然后还它显示的结果，我想多种方法但失败。

我需要，如果这些领域的任何一个是空的，那么它不会显示结果。

看到完整的代码here

Answer 1

检查是否$字段为空或is_null
也有是在你的代码一个错字

<input type="text" name="txtwasitto" placeholder="Wasit To" /> 

将其更改为

<input type="text" name="txtwaistto" placeholder="Wasit To" /> 

化妆确定你从$ _POST删除XSS

$fields = array('ageid', null, 'heightid', null, 'waistid'); //database fields 
$txtfields = array('txtagefrom', 'testnull', 'txtheightfrom', 'testnull', 'txtwaistfrom'); //from range 
$txttofields = array('txtageto', 'testnull', 'txtheightto', 'testnull', 'txtwaistto'); // To Range 

$conditions = array(); 
foreach (array_map(NULL, $fields, $txtfields, $txttofields) as $x) { 
    list($fields, $txtfields, $txttofields) = $x; 
    if(!empty($_POST[$txtfields]) && !empty($_POST[$txttofields])) 
    echo "'" . $fields . "' between '" . $_POST[$txtfields] . "' And '" . $_POST[$txttofields] . "'"; 
}