SQL排序问题

Question

我想要检索表中的所有值，按字母顺序排序并将“全部”附加到顶部（全部不在表格中）。

当前代码：

SELECT 0 AS TypeID, 'All' AS [Type] 
UNION 
SELECT TypeID, [Type] FROM tbl_Type ORDER BY 2 

此订单的一切，包括所有的，这是有问题的，因为我在这台所谓的“协议”，这之后的排序显示了之前所有的值。

有没有什么办法可以返回一个列表顶部的“全部”和其下的所有东西？

UPDATE：

我试图通过Andomar和康拉德建议的解决方案，但是我得到以下错误：

Msg 207, Level 16, State 1, Line 4 
Invalid column name 'Type'. 
Msg 104, Level 16, State 1, Line 4 
ORDER BY items must appear in the select list if the statement contains a UNION, INTERSECT or EXCEPT operator. 

Answer 1

你可以使用case排序'全部'前面：

SELECT 0 AS TypeID, 'All' AS [Type] 
UNION 
SELECT TypeID, [Type] FROM tbl_Type 
ORDER BY case when Type = 'All' then 1 else 2 end, Type 

编辑：根据您的评论，SQL Server不允许order by别名。使用子查询：

SELECT * 
FROM (
     SELECT 0 AS TypeID, 'All' AS [Type] 
     UNION 
     SELECT TypeID, [Type] FROM tbl_Type 
     ) as SubQueryAlias 
ORDER BY case when Type = 'All' then 1 else 2 end, Type 

或在这种情况下，因为类型是一个实际的表中的字段，而不是一个别名，交换联盟的两个部分：

SELECT TypeID, [Type] FROM tbl_Type 
UNION 
SELECT 0 AS TypeID, 'All' AS [Type] 
ORDER BY case when Type = 'All' then 1 else 2 end, Type 

Answer 2

随着Andomar的答案，你也可以做到这一点来解决别名问题。

WITH CTE As 
(

    SELECT 0 AS TypeID, 'All' AS [Type] 
    UNION 
    SELECT TypeID, [Type] FROM tbl_Type 
    ORDER BY 
) 
SELECT 
    typeID, 
    Type, 
FROM 
     CTE 
ORDER BY 
    CASE 
     WHEN TypeID = 0 THEN typeID 
     ELSE Type 
    END 

但这种假设tbl_type.type的所有值都大于0

你也可以添加其他字段的CTE

WITH CTE As 
(

    SELECT 0 AS TypeID, 'All' AS [Type], 1 as sortorder 
    UNION 
    SELECT TypeID, [Type] FROM tbl_Type, 2 as sortorder 
    ORDER BY 
) 
SELECT 
    typeID, 
    Type, 
FROM 
     CTE 
ORDER BY 
    sortorder, 
    type 

Answer 3

SELECT 0 AS TypeID, 'All' AS [Type] UNION SELECT TypeID, [Type] FROM tbl_Type ORDER BY 2 DESC 

Answer 4

你可以只添加第三列进行排序，其指示它是否是一个数据记录（或 “全部”）

SELECT 0 AS TYPEID， '全部' AS [类型]，0 AS IsDataRecord UNION SELECT TYPEID，[类型]，1 AS IsDataRecord FROM tbl_Type ORDER BY 3， 2