2017-02-07 115 views
0

我与测量值的列表,如:“列表”对象没有属性“方法”

[[Measurements(100, 0.3)], 
[Measurements(33, 0.5)]] 

然后,我有一些标准的列表,其包含的测量列表:

[Criteria(999, [[Measurements(100, 0.3)], 
         [Measurements(33, 0.5)]])], 

[Criteria(999, [[Measurements(150, 0.3)], 
         [Measurements(35, 0.5)]])] 

最后,我想提供上述列表作为输入并执行代码:

class Measurements(): 
    def __init__(self, value, other): 
     self.value = value 
     self.other = other 


class Criteria(): 
    def __init__(self, new_value, measurements): 
     self.new_value = new_value 
     self.measurements = measurements 

    def method(self): 

     # Here, I am iterating through all measurements 
     # and replace the value according to criteria 
     for idx, x in enumerate(self.measurements): 
      if (self.measurements[idx].value > 20 and 
        self.measurements[idx].value < 110): 

       self.measurements[idx].value = self.new_value 
     return self.measurements 


class Evaluate(): 
    def __init__(self, criteria): 
     self.criteria = criteria 

    def execute(self): 
     criteria = self.criteria 

     # Here, I am iterating through all criteria 
     # and call the method from criteria 
     for i, c in enumerate(criteria): 
      c.method() 
      return c.measurements 


def main(): 

    criteria = [ 
     [Criteria(999, [[Measurements(100, 0.3)], 
         [Measurements(33, 0.5)]])], 

     [Criteria(999, [[Measurements(150, 0.3)], 
         [Measurements(35, 0.5)]])] 
    ] 

    obs = (Evaluate(criteria).execute()) 


if __name__ == "__main__": 
    main() 

和我收到c.method() AttributeError: 'list' object has no attribute 'method'

我想我的结果是新的校正测量,所以:

[[Measurements(999, 0.3)], 
[Measurements(999, 0.5)]], 
[Measurements(150, 0.3)], 
[Measurements(999, 0.5)]] 
+4

为什么你有嵌套的列表? 'C'是'[标准(999,...)]',在它的一个元件的列表,*不*'标准(999,...)'。 –

+0

我有嵌套列表,因为我会有很多标准,我想评估。 – George

+1

那并不需要*嵌套*名单.. –

回答

2

你所有的Criteria()Measurement()对象中的每个存储在一个元素的列表,而这又是存储在一个较大名单。要么为此考虑,要么不使用单元素嵌套列表。

我没有看到这些单元素列表的任何理由;下面的定义应该让你的代码工作:

criteria = [ 
    Criteria(999, [Measurements(100, 0.3), Measurements(33, 0.5)]), 
    Criteria(999, [Measurements(150, 0.3), Measurements(35, 0.5)]), 
] 

你反之则要要么提取每一次,或使用嵌套循环一个元素:

def execute(self): 
    for c in self.criteria: 
     c[0].method() 

def execute(self): 
    for c_list in self.criteria: 
     for c in c_list: 
      c.method() 

您还应该而不是for循环中使用return,至少在您想要测量全部标准。将测量值收集到列表中,然后返回该列表。

您还在Criteria.method()循环中使用self太多次。不需要enumerate(),您不需要索引来更改可变对象。

更正代码:

class Measurements(): 
    def __init__(self, value, other): 
     self.value = value 
     self.other = other 


class Criteria(): 
    def __init__(self, new_value, measurements): 
     self.new_value = new_value 
     self.measurements = measurements 

    def method(self): 
     for measurement in self.measurements: 
      if 20 < measurement.value < 110: 
       measurement.value = self.new_value 
     return self.measurements 

class Evaluate(): 
    def __init__(self, criteria): 
     self.criteria = criteria 

    def execute(self): 
     results = [] 
     for c in self.criteria: 
      measurements = c.method() 
      results.extend(measurements) 
     return results 

def main(): 
    criteria = [ 
     Criteria(999, [Measurements(100, 0.3), Measurements(33, 0.5)]), 
     Criteria(999, [Measurements(150, 0.3), Measurements(35, 0.5)]), 
    ] 

    obs = Evaluate(criteria).execute() 
+0

好了,感谢您的帮助和建议!所以,我的主要问题是嵌套列表,并没有在所有的循环工作!至于回报,在它会只返回第一个计算,对吗?(upvoted) – George

+0

@George:完全; 'return'将在那里退出函数,所以只返回第一个结果。 –

+0

谢谢you.Can你告诉我[此情况下(http://pastebin.com/Dc7dzaVp)我怎么能对付回报,如果我有很多情况下? (我的意思是,好,我可以有很多的在任何情况下的循环,但我不知道是否还有别的东西) – George