MySQL查询与GROUP BY和JOIN

Question

下午好，

我想从我的MySQL数据库获得一些信息，我有问题，因为我不能够有所需的信息。我尝试了很多不同的方法，但他们都没有工作。我希望你能找到的东西，因为我非常接近找到解决办法，但缺少的东西：

MySQL查询：

SELECT b.id, b.tipo_perfil, round(avg(b.edad)), COUNT(c.zona), c.zona 
FROM analizador_datos_usuario AS a 
INNER JOIN analizador_datos_perfil AS b ON (a.id_usuario = b.id_perfil) 
INNER JOIN analizador_datos_perfil_historial AS c ON (b.id = c.id_perfil) 
WHERE a.id_usuario=21 
GROUP BY b.tipo_perfil, c.zona 
ORDER BY b.tipo_perfil ASC, count(c.zona) DESC 

该查询给我下面的信息：

表（红色是我需要的）：

周

亲切的问候，

Answer 1

尝试：

SELECT b.tipo_perfil, round(avg(b.edad)), COUNT(distinct c.zona), group_concat(distinct b.id separator ' ') as id_list, group_concat(distinct c.zona separator ' ') as zona_list 
FROM analizador_datos_usuario AS a 
INNER JOIN analizador_datos_perfil AS b ON (a.id_usuario = b.id_perfil) 
INNER JOIN analizador_datos_perfil_historial AS c ON (b.id = c.id_perfil) 
WHERE a.id_usuario=21 
GROUP BY b.tipo_perfil 
ORDER BY b.tipo_perfil ASC, count(distinct c.zona) DESC 

Answer 2

我觉得你得到的结果显示什么，你想要得到它是红色。从`select`

SELECT b.id, b.tipo_perfil, round(avg(b.edad)), COUNT(c.zona) counted_zone, c.zona 
FROM analizador_datos_usuario AS a 
INNER JOIN analizador_datos_perfil AS b ON (a.id_usuario = b.id_perfil) 
INNER JOIN analizador_datos_perfil_historial AS c ON (b.id = c.id_perfil) 
WHERE a.id_usuario=21 
GROUP BY b.tipo_perfil, c.zona 
Having MAX(counted_zone) 
ORDER BY b.tipo_perfil ASC, counted_zone DESC