矛盾的问题在哪里条款

Question

我想显示每个用户花了他们的时间做一周（内部或外部工作），但时间都在表上的同一列，是否有可能分裂它分成2个不同的列，并且仍然具有这样的功能，因此它只显示每个用户一次不是每次输入时间，而这一次可能在整个星期内多次。

下面的SQL给我每个用户跟踪一周的时间，但不同行的内部和外部。

SELECT SUM(FilteredMag_Time.mag_hoursspent) AS Time, 
     FilteredSystemUser.fullname, 
     FilteredMag_project.mag_typename 
    FROM FilteredSystemUser 
INNER JOIN FilteredMag_Task 
INNER JOIN FilteredMag_project ON FilteredMag_Task.mag_projectid = FilteredMag_project.mag_projectid 
INNER JOIN FilteredMag_Time ON FilteredMag_Task.mag_taskid = FilteredMag_Time.mag_taskid 
          ON FilteredSystemUser.systemuserid = FilteredMag_Time.createdby 
    WHERE (FilteredMag_Time.mag_starttime BETWEEN DATEADD(dd, - (DATEPART(dw, GETDATE()) - 1), GETDATE()) 
               AND DATEADD(dd, - (DATEPART(dw, GETDATE()) - 7), GETDATE())) 
GROUP BY FilteredSystemUser.fullname, FilteredMag_project.mag_typename 
ORDER BY FilteredSystemUser.fullname 

以下是当前输出示例。

Time    fullname    mag_typename 
------------------ --------------------- ------------------------- 
1.2500000000  David Sutton  External 
8.2500000000  Gayan Perera  External 
9.0000000000  Paul Nieuwelaar  Internal 
14.8700000000  Roshan Mehta  External 
6.0000000000  Roshan Mehta  Internal 
2.7800000000  Simon Phillips  External 
4.6600000000  Simon Phillips  Internal 

Answer 1

假设FilteredMag_project.mag_typename是 '内部' 或 '外部'，请尝试以下操作：

SELECT SUM(CASE FilteredMag_project.mag_typename 
       WHEN 'INTERNAL' THEN FilteredMag_Time.mag_hoursspent 
       ELSE 0 END) AS InternalTime, 
     SUM(CASE FilteredMag_project.mag_typename 
       WHEN 'EXTERNAL' THEN FilteredMag_Time.mag_hoursspent 
       ELSE 0 END) AS ExternalTime, 
     FilteredSystemUser.fullname 
    FROM FilteredSystemUser 
INNER JOIN FilteredMag_Task 
INNER JOIN FilteredMag_project ON FilteredMag_Task.mag_projectid = FilteredMag_project.mag_projectid 
INNER JOIN FilteredMag_Time ON FilteredMag_Task.mag_taskid = FilteredMag_Time.mag_taskid 
          ON FilteredSystemUser.systemuserid = FilteredMag_Time.createdby 
    WHERE (FilteredMag_Time.mag_starttime BETWEEN DATEADD(dd, - (DATEPART(dw, GETDATE()) - 1), GETDATE()) 
               AND DATEADD(dd, - (DATEPART(dw, GETDATE()) - 7), GETDATE())) 
GROUP BY FilteredSystemUser.fullname 
ORDER BY FilteredSystemUser.fullname 

Answer 2

您可以使用SQL Server PIVOT。

喜欢的东西

DECLARE @Table TABLE(
     userID INT, 
     typeID VARCHAR(20), 
     TimeSpent FLOAT 
) 

INSERT INTO @Table SELECT 1, 'INTERNAL', 1 
INSERT INTO @Table SELECT 2, 'INTERNAL', 1 
INSERT INTO @Table SELECT 1, 'INTERNAL', 1 
INSERT INTO @Table SELECT 1, 'INTERNAL', 1 
INSERT INTO @Table SELECT 2, 'EXTERNAL', 3 
INSERT INTO @Table SELECT 1, 'EXTERNAL', 3 

SELECT * 
FROM 
(
    SELECT userID, typeID, TimeSpent 
    FROM @Table 
) s 
PIVOT (SUM(TimeSpent) FOR typeID IN ([INTERNAL],[EXTERNAL])) pvt 

输出：

userID  INTERNAL    EXTERNAL 
----------- ---------------------- ---------------------- 
1   3      3 
2   1      3