蛮力算法停止循环

Question

我试图让三个数字的组合增加到810并乘以10760040.这是我迄今为止;

x = 1 
y = 1 
z = 1 

keepGoing = 1 

while keepGoing == 1: 
    if x+y+z == 810: 
     if x*y*z == 10760040: 
      print(x) 
      print(y) 
      print(z) 
     else: 
      keepGoing = 2 
      z = 1 
      print("no z") 
     elif z == 810: 
     keepGoing = 2 
     print("no") 
    else: 
     z += 1 




while keepGoing == 2: 
    if x+y+z == 810: 
     if x*y*z == 10760040: 
      print(x) 
      print(y) 
      print(z) 
     else: 
      keepGoing = 3 
      z = 1 
      y = 1 
      print("no y") 

    elif y == 810: 
     keepGoing = 3 
    else: 
     z += 1 
     keepGoing = 1 

while keepGoing == 3: 
    if x+y+z == 810: 
     if x*y*z == 10760040: 
      print(x) 
      print(y) 
      print(z) 
      print("Success") 
     else: 
      print("Failure") 
    elif x == 810: 
     print("none") 
    else: 
     x += 1 
     keepGoing = 1 

我知道这个代码是reaaaally基本的，但我没有在很长一段时间做过任何Python和我试图找到添加使810繁衍到10760040，任何帮助将号码列表太棒了，谢谢！

Answer 1

一个更清洁，更简单的代码是：

for x in range(1,810): 
    for y in range(1,810-x): 
     z = 810-x-y 
     if x*y*z == 10760040: 
      print 'x={},y={},z={}'.format(x,y,z)