2010-10-21 123 views
0

我有数据,遵循这种彭定康:数据收集任务

ID  Name1  Name2 Name3 Name4 ..... 
41242 MCJ5X  TUAW  OXVM4 Kcmev 1 
93532 AVEV2  WCRB3 LPAQ 2 DVL2 
. 
. 
. 

截至目前,这是一个电子表格只是格式,并具有约6000行。我需要做的是在Name1之后为每个Name创建一个新行,并将其与当前行的ID相关联。例如,见下:

ID  Name1 
41242 MCJ5X  
41242 TUAW  
41242 OXVM4  
41242 Kcmev 1 
93532 AVEV2  
93532 WCRB3  
93532 LPAQ 2 
93532 DVL2 

任何想法,我可以做到这一点?我觉得这不应该太复杂,但不能确定最好的方法。无论是剧本还是某个功能,我都会非常感谢帮助。

+0

任何语言特别?任何文字处理lang都可以。你用awk吗? – 2010-10-21 04:11:15

回答

0

如果可能,您可能需要使用csv文件。这些文件是纯文本的,大多数电子表格程序可以打开/修改它们(我知道Excel和OpenOffice版本可以)。如果你采用这种方法,你的算法看起来像这样:

read everything into a string array 
create a 1 to many data structure (maybe a Dictionary<string, List<string>> or list of (string, string) tuple types) 

loop over each line of the file 
splice the current line on the ','s and loop over those 
if this is the first splice, add a new item to the 1 to many data structure with the current splice as the Id 
otherwise, add this splice to the "many" (name) part of the last item in the data structure 

create a new csv file or open the old one for writing 
output the "ID, Name1" row 
loop over each 1-many item in the data collection 
loop over the many items in the current 1-many item 
output the 1 (id) + "," + current many item (current name) 

你可以用任何语言来做到这一点。如果它是一次性使用脚本,那么Python,Ruby或Powershell(取决于平台)可能是一个不错的选择。