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我移植我gtkmm2到gtkmm3应用程序,这是我到目前为止有:的Gtk ::窗口显示和退出,而我移植到gtkmm2应用gtkmm3
// The main.cxx:
#include "alarmui.hxx"
int main (int argc, char *argv[]) {
Glib::RefPtr<Gtk::Application> app = Gtk::Application::create(argc, argv, "org.gtkmm." PACKAGE_ID);
alarm_ui win(app);
app->run();
return 0;
}
页眉:
// The alarmui.hxx
#ifndef ALARMUI_HXX_INC
#define ALARMUI_HXX_INC
#ifdef HAVE_CONFIG_H
#include "config.h"
#endif
#include <gtkmm/application.h>
#include <gtkmm/window.h>
#include <gtkmm/statusicon.h>
#include <iostream>
#include <memory>
#include <functional>
class alarm_ui : public Gtk::Window
{
private:
Glib::RefPtr<Gtk::Application> _refApp;
Glib::RefPtr<Gtk::StatusIcon> m_status_icon;
public:
alarm_ui (Glib::RefPtr<Gtk::Application>&);
virtual ~alarm_ui();
protected:
virtual bool delete_event (GdkEventAny*);
void status_icon_activate_cb();
};
#endif
源代码:
#include "alarmui.hxx"
alarm_ui::alarm_ui (Glib::RefPtr<Gtk::Application>& refApp) : _refApp(refApp)
{
std::cout << "init" << std::endl;
set_icon_from_file (ICON_PNG_PATH);
m_status_icon = Gtk::StatusIcon::create_from_file (ICON_PNG_PATH);
m_status_icon->signal_activate().connect (std::bind(&alarm_ui::status_icon_activate_cb, this));
show_all();
}
alarm_ui::~alarm_ui() {
std::cout << "done" << std::endl;
}
bool alarm_ui::delete_event (GdkEventAny* event) {
return false;
}
void alarm_ui::status_icon_activate_cb() {
if (get_visible()) {
iconify();
hide();
} else {
deiconify();
show();
}
}
我想表明我的一个状态图标窗口。切换窗口的可见性,同时点击状态图标。代码编译好,但似乎当我执行二进制的构造函数和析构函数被调用。如果我用的是这样的:
Glib::RefPtr<Gtk::Application> app = Gtk::Application::create(argc, argv, "org.gtkmm." PACKAGE_ID);
alarm_ui win(app);
app->run (win);
窗户节目,但是...如预期,退出上的hide()命令...任何想法? 是否只有()和释放()我唯一的选择?
是的,似乎在构造函数上使用hold()和在析构函数上使用realease()或quit()。 – Joel 2015-04-11 00:59:32