函数错误中的Python函数？

Question

我写了这个作为一个例子：

def function(): 
choice = raw_input("> ") 
if choice == "attack": 
    print "Killed the monster." 
elif choice == "run": 
    print "You run but the monster follows you. Activate jetpack? (y/n)" 
    def function_in_function(): 
     choice = raw_input("> ") 
     if choice == "y": 
      print "You fly to safety." 
     elif choice == "n": 
      print "You get stomped." 
     else: 
      print "That's not an option." 
      function_in_function() 
else: 
    print "That's not an option." 
    function() 

我打开了它的电源外壳，但一无所获？

Answer 1

我想这是你想要的功能和格式。我不建议在这里使用函数内部的函数，因为它不是必需的，但它仍然可以如图所示完成。记住缩进。在这里阅读http://www.python-course.eu/python3_blocks.php。另外，在分配它之前，您不能调用函数。

def function(): 

    choice = raw_input("> ") 
    if choice == "attack": 
     print "Killed the monster." 
    elif choice == "run": 
     print "You run but the monster follows you. Activate jetpack? (y/n)" 
     def function_in_function(): 
      choice = raw_input("> ") 
      if choice == "y": 
       print "You fly to safety." 
      elif choice == "n": 
       print "You get stomped." 
      else: 
       print "That's not an option." 
       function_in_function() 
     function_in_function() 
    else: 
     print "That's not an option." 
     function() 


function() 

编辑：根据评论。