2013-04-15 67 views
0

请帮我解决问题,我无法在表格格式中显示下面的“out.println”数据。需要以表格格式显示out.println命令数据

if(rs.next())   
{   
out.println(rs.getString("Case_Title"));   
out.println(rs.getString("Problem_Descr"));   
out.println(rs.getString("Problem_Submit"));   
}   
}   
catch(Exception e)   
{   
e.printStackTrace();   
}   

回答

0

尝试这样

<% 
    while (rs.next()) { 
%> 
<p ><%=rs.getString("Case_Title")%></p> 
<p ><%=rs.getString("Problem_Descr")%></p> 
<p ><%=rs.getString("Problem_Submit")%></p> 

<% 
    } 
%> 

avoid scriplets ,如果可能的话

+0

@ badshah..its不工作在应用下面的代码后得到错误 –

0

使用以下代码::

<table> 
    if(rs.next())   
    {   
     out.println("<tr>"); 
     out.println("<td>"); 
     out.println(rs.getString("Case_Title"));   
     out.println("</td>"); 
     out.println("<td>"); 
     out.println(rs.getString("Problem_Descr"));   
     out.println("</td>"); 
     out.println("<td>"); 
     out.println(rs.getString("Problem_Submit"));   
     out.println("</td>"); 
     out.println("</tr>"); 
    }   
    }   
    catch(Exception e)   
    {   
     e.printStackTrace();   
    } 
<table>