Python可变增量while循环

Question

我试图让变量number增加，如果用户猜对了正确的数字！如果被另一个用户猜测，则继续增加增加的一个。但这似乎是我的syntax是错误的。所以我真的需要你的帮助。贝娄是我的代码：

#!/usr/bin/python 
# Filename: while.py 
number = 23 
running = True 

while running: 
    guess = int(raw_input('Enter an integer : ')) 

    if guess == number: 
     print 'Congratulations, you guessed it. The number is now increase' 
     number += 1 # Increase this so the next user won't know it! 
     running = False # this causes the while loop to stop 
    elif guess < number: 
     print 'No, it is a little higher than that.' 
    else: 
     print 'No, it is a little lower than that.' 
else: 
    print 'The while loop is over.' 
    # Do anything else you want to do here 
print 'Done' 

Answer 1

#!/usr/bin/python 
# Filename: while.py 
number = 23 
running = True 

while running: 
    guess = int(raw_input('Enter an integer : ')) 

    if guess == number: 
     print 'Congratulations, you guessed it. The number is now increase' 
     number += 1 # Increase this so the next user won't know it! 
     running = False # this causes the while loop to stop 
    elif guess < number: 
     print 'No, it is a little higher than that.' 
    else: 
     print 'No, it is a little lower than that.' 

# Do anything else you want to do here 
print 'Done' 

Answer 2

你可以不用“跑”变量，它不需要

#!/usr/bin/python 
# Filename: while.py 
number = 23 
import sys 

try: 
    while True: 
     guess = int(raw_input('Enter an integer : ')) 
     if guess == number: 
      print('Congratulations, you guessed it. The number is now increase') 
      number += 1 # Increase this so the next user won't know it! 
     elif guess < number: 
      print('No, it is a little higher than that.') 
     else: 
      print('No, it is a little lower than that.') 
except ValueError: 
    print('Please write number') 
except KeyboardInterrupt: 
    sys.exit("Ok, you're finished with your game") 

Answer 3

我不正常，你想做什么都知道，因为我初学者。但我知道你的代码中有一件事是错误的，那就是你在while循环后输入了其他东西。你的代码实际上没有意义，或者你的缩进是错误的，或者它是一个错误的代码，因为只有在你使用if之后才能输入。