笨开始和结束日期验证

Question

我得到准确的结果，如果我设定开始日期和结束日期时，年份是2017年。但是，当开始日期15月-2016到15日至2017年它不工作，并显示错误MESSAGE-

$error = "End date can't be older than begin date "; 

这里是我的代码

 $data['beginDate'] = $this->input->post('beginDate'); 
     $data['endDate'] = $this->input->post('endDate'); 

     if($data['endDate'] < $data['beginDate']){ 
      $error = "End date can't be older than begin date "; 
      $this->session->set_flashdata('error', $error); 
      redirect('/search'); 
     } 
     else{ 
      $this->load->model('personhistory'); 
      $data['rets'] = $this->personhistory->searchDetails(); 
      $data['sum'] = $this->personhistory->searchDetailsSum(); 
      $data['title'] = "Search Details"; 
      $this->load->view('search_results', $data); 
     } 

有什么解决方案来摆脱这个问题的？请帮助...

Answer 1

PHP不知道你的字符串是什么，如果值从发布的数据到来，那么他们都是字符串：

// These are strings 
$s1 = '15-October-2016'; 
$s2 = '15-September-2016'; 

相反，你需要为创建datetime对象的比较

$d1 = new DateTime('15-October-2016'); 
$d2 = new DateTime('15-September-2016'); 

if($d1 < $d2) 
    echo 'First date comes before the second date'; 

if($d1 > $d2) 
    echo 'First date comes after the second date'; 

if($d1 == $d2) 
    echo 'First date and second date are the same'; 

试试这段代码并改变日期，你会看到我是对的。

UPDATE：

从技术上讲，你也可以使用的strtotime

<?php 

$s1 = strtotime('15-October-2016'); 
$s2 = strtotime('15-September-2016'); 

if($s1 < $s2) 
    echo 'First date comes before the second date'; 

if($s1 > $s2) 
    echo 'First date comes after the second date'; 

if($s1 == $s2) 
    echo 'First date and second date are the same';