在React Native + Redux中,我有一个可运行的React Native Drawer https://github.com/root-two/react-native-drawer,但试图使用NavigationExperimental
来实现导航按钮,更具体地说是NavigationCardStack
。所以,我创建了抽屉三个按钮,当我试图在它们之间进行导航,我得到一个错误:should not push route with duplicated key
(例如,如果我按ProfilePage
按钮,然后HomePage
按钮,然后ProfilePage
一遍,然后我会得到错误)React Native:如何使用NavigationExperimental正确实现React Native Drawer的导航?
可能是什么问题?我的导航是否正确?如果不是,使用React Native Drawer上的导航按钮在场景之间导航的正确方法是什么?
这里是我的设置:
_renderScene (props) {
const { route } = props.scene
return (
<route.component _handleNavigate={this._handleNavigate} actions={this.props}/>
)
}
_handleBackAction() {
if (this.props.navigation.index === 0) {
return false
}
this.props.popRoute()
return true
}
_handleNavigate(action) {
switch (action && action.type) {
case 'push':
this.props.pushRoute(action.route)
return true
case 'back':
case 'pop':
return this._handleBackAction()
default:
return false
}
}
<Drawer
content={<DrawerPanel {...this.props} _handleNavigate={this._handleNavigate}/>}
openDrawerOffset={100}
ref={(ref) => this._drawer = ref}
type='static'
tweenHandler={Drawer.tweenPresets.parallax}
tapToClose
acceptPan
negotiatePan
>
<NavigationCardStack
direction='horizontal'
navigationState={this.props.navigation}
onNavigate={this._handleNavigate}
renderScene={this._renderScene}
/>
</Drawer>
在印刷机上使用_handleNavigate(route)
有关阵营本地抽屉导航按钮,这就是route
怎么会被格式化:
const route = {
group: {
type: 'push',
route: {
key: 'profilepage',
title: 'ProfilePage',
component: ProfilePage,
direction: 'horizontal',
},
}
}
而且.push
和.pop
由我处理naviReducer.js
import { PUSH_ROUTE, POP_ROUTE } from '../Constants/ActionTypes'
import { NavigationExperimental } from 'react-native'
import Login from '../Components/Login'
const {
StateUtils: NavigationStateUtils
} = NavigationExperimental
const initialState = {
index: 0,
key: 'root',
routes: [{
key: 'login',
title: 'Login',
component: Login,
unique: true,
direction: 'horizontal',
}]
}
function navigationState (state = initialState, action) {
if(action.type == PUSH_ROUTE && action.route.unique==true)
{
if(state.routes.find(child => child.key === key))
{
return NavigationStateUtils.jumpTo(state, action.route.key)
}
}
switch(action.type) {
case PUSH_ROUTE:
if (state.routes[state.index].key === (action.route && action.route.key)) return state
return NavigationStateUtils.push(state, action.route)
case POP_ROUTE:
if (state.index === 0 || state.routes.length === 1) return state
return NavigationStateUtils.pop(state)
default:
return state
}
}
export default navigationState