无法使用请求

Question

张贴在usergrid文件我能够发布文件，curl

curl -X POST -i -F name='memo.txt' -F file=@/home/tester/Desktop/memo.txt 
'http://localhost:8080/***/***/concerts/008? 
access_token=YWMtraI2DF21EeWx_Rm4tdnmrwAAAVACjcyGG8TpdXJBXdjnRJ2SeqIAZI1T8Xk' 

但是，当我试图用requests.post同样的事情，文件没有上传到服务器。有人知道为什么会发生这种情况。

import requests 

url = 'http://localhost:8080/***/***/concerts/008' 
files = { 
    'memo.txt': open('/home/tester/Desktop/memo.txt', 'rb'), 
    'name': 'memo.txt' 
} 
r = requests.post(
    url, files=files, 
    params=dict(access_token='YWMtraI2DF21EeWx_Rm4tdnmrwAAAVACjcyGG8TpdXJBXdjnRJ2SeqIAZI1T8Xk') 
) 

Answer 1

你似乎缺少name场，添加到您的files字典，或到一个新的data字典（无论是罚款）。您的文件应该命名为file：

import requests 

url = 'http://localhost:8080/***/***/concerts/008' 
files = {'file': open('/home/tester/Desktop/memo.txt','rb')} 
data = {'name': 'memo.txt'} 
params = {'access_token': 'YWMtraI2DF21EeWx_Rm4tdnmrwAAAVACjcyGG8TpdXJBXdjnRJ2SeqIAZI1T8Xk'} 
r = requests.post(url, data=data, files=files, params=params) 

或

import requests 

url = 'http://localhost:8080/***/***/concerts/008' 
files = { 
    'file': open('/home/tester/Desktop/memo.txt','rb'), 
    'name': 'memo.txt' 
} 
params = {'access_token': 'YWMtraI2DF21EeWx_Rm4tdnmrwAAAVACjcyGG8TpdXJBXdjnRJ2SeqIAZI1T8Xk'} 
r = requests.post(url, files=files, params=params)