SQLite的更新多条记录与不同的值由查询

Question

我的情况如下（SQLfiddle）给出：

我有两个表People和Scores，他们看起来是这样的：

CREATE TABLE People 
(
    name TEXT, 
    minScore INTEGER, 
    maxScore INTEGER, 
    FOREIGN KEY (minScore) REFERENCES B(rowid), 
    FOREIGN KEY (maxScore) REFERENCES B(rowid) 
); 

INSERT INTO People (name) VALUES ('Terry'); 
INSERT INTO People (name) VALUES ('Bob'); 

CREATE TABLE Scores 
(
    nameID INTEGER, 
    score INTEGER, 
    FOREIGN KEY (nameID) REFERENCES A(rowid) 
); 

INSERT INTO Scores (nameID, score) VALUES (1, 10); 
INSERT INTO Scores (nameID, score) VALUES (1, 8); 
INSERT INTO Scores (nameID, score) VALUES (1, 5); 
INSERT INTO Scores (nameID, score) VALUES (2, 12); 
INSERT INTO Scores (nameID, score) VALUES (2, 8); 
INSERT INTO Scores (nameID, score) VALUES (2, 2); 

我想更新People表以包含其minScore和maxScore的rowID。我怎么做？

目的：

Terry | 5 | 10 
Bob | 2 | 12 

这是我曾尝试：

CREATE VIEW minScores 
AS 
    SELECT Scores.rowid AS scoreID, Scores.nameID AS nameID 
    FROM Scores 
    WHERE score IN (SELECT MIN(score) 
        FROM Scores AS Scores2 
        GROUP BY Scores2.nameID); 

UPDATE People 
SET minScore = (SELECT scoreID FROM minScores) 
WHERE People.rowid IN (SELECT nameID FROM minScores) 

刚刚填充表的最后一个最小值。

（我不得不使用一个观点，因为我无法了解如何使用工作...）

Answer 1

你更新使用scalar subquery;其值

是所附SELECT语句结果的第一行。换句话说，隐含的“LIMIT 1”被添加到子查询中。

要获取不同的行不同的结果，你必须使用一个correlated subquery：

UPDATE People 
SET minScore = (SELECT rowid 
       FROM Scores 
       WHERE Scores.nameID = People.rowid 
       ORDER BY score ASC), 
    maxScore = (SELECT rowid 
       FROM Scores 
       WHERE Scores.nameID = People.rowid 
       ORDER BY score DESC); 

（你不应该使用外键隐含rowid;其价值can change）