迅速：改变数组的内容给我一个错误

我有此数组：迅速：改变数组的内容给我一个错误

var array = [[12,46,["a","b","c"],"nil",true,7,true],[10,40,["c","d","e"],"nil",true,7,true],[0,1,["z","l","w"],"hey",false,7,true]].

，当我试图通过这个代码更改数组布尔的最后一个布尔值：

array[0][6] = false

我得到这个错误“不能通过下标下标是只能获取数组”

来源

2016-06-29 Theilya

有趣。我认为编译器绊倒了某个地方。你只需要检查阵列的类型来理解为什么：

var array = [ 
    [12,46,["a","b","c"],"nil",true,7,true], 
    [10,40,["c","d","e"],"nil",true,7,true], 
    [0,1,["z","l","w"],"hey",false,7,true] 
] 

print(array.dynamicType) // Array<NSArray> 
         // can't assign to the inner array since NSArray is immutable

给斯威夫特内型的暗示和它的作品

var array: [[AnyObject]] = [ 
    [12,46,["a","b","c"],"nil",true,7,true], 
    [10,40,["c","d","e"],"nil",true,7,true], 
    [0,1,["z","l","w"],"hey",false,7,true] 
] 

array[0][6] = false  // works

来源

2016-06-29 01:00:41

谢谢你已经工作了！ – Theilya

我不知道为什么Swift编译器默认为非Swift本机类型'NSArray'？ –

，您应该使用的元组数组来代替。使更好的代码，执行更好，并且不依赖于Objective-C：

var array = [ 
    (12,46,["a","b","c"],"nil",true,7,true), 
    (10,40,["c","d","e"],"nil",true,7,true), 
    (0,1,["z","l","w"],"hey",false,7,true) 
] 

// Array has type [(Int, Int, [String], String, Bool, Int, Bool)] 

array[0].6 = false

来源

2016-06-29 01:08:01 Kametrixom

这澄清程序员的目的，特别是因为外阵列的所有条目具有相同的结构（'Int'，'Int'，'[字符串]'，'String'，'Bool'，'Int'，'Bool'）。 –

迅速：改变数组的内容给我一个错误

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