2
我试图根据这两个值显示不同的颜色。值比较不能按预期工作
的所有如果值是相等的,那么首先显示绿色,工作正常
<?php if (miletofurlong($pasthorse['distance']) == $todaysdistance)
{
$Horsedist = "<b><span style='color:#ff4500 '>". miletofurlong($pasthorse['distance'])."f</span></b>";
} ?>
现在我想要做的是,如果miletofurlong($pasthorse['distance'])
不等于但仍之间($ todaysdistance + 1)和($ todaysdistance + 1),然后将其突出显示为蓝色。
我已经跑了下面的代码,但它似乎要突出的一切,我不能确定为什么
if (miletofurlong($pasthorse['distance']) == $todaysdistance)
{
$Horsedist = "<b><span style='color:#ff4500 '>". miletofurlong($pasthorse['distance'])."f</span></b>";
}
elseif (miletofurlong($pasthorse['distance']) !== $todaysdistance and miletofurlong($pasthorse['distance']) <= ($todaysdistance + 1) or miletofurlong($pasthorse['distance']) !== $todaysdistance and miletofurlong($pasthorse['distance']) >= ($todaysdistance - 1) )
{
$Horsedist = "<b><span style='color:blue'>". miletofurlong($pasthorse['distance'])."f</span></b>". ($todaysdistance + 1). "and" . ($todaysdistance - 1);
}
else
{
$Horsedist = miletofurlong($pasthorse['distance'])."f" ;
}
您是否正确地检查了这部分? *“但仍然在($ todaysdistance + 1)和($ todaysdistance + 1)之间”*两个相同的数字之间怎么样? –
可能这会帮助你取代第二种情况elseif((miletofurlong($ pasthorse ['distance'])!== $ todaysdistance && miletofurlong($ pasthorse ['distance'])<=($ todaysdistance + 1)) ||(miletofurlong($ pasthorse ['distance'])!== $ todaysdistance && miletofurlong($ pasthorse ['distance'])> =($ todaysdistance - 1))) –